Answer:
-2.2y - 1.8
Step-by-step explanation:
We are to simplify the expression:
1.2y + 4.5 - 3.4y - 6.3
Collect like terms:
1.2y - 3.4y + 4.5 - 6.3
Simplify:
-2.2y - 1.8
That is the answer.
If a function is even, then f(-x) = x.
If a function is odd, then f(-x) = -x.
y = x³ + x² → f(x) = x³ + x² → -f(x) = -(x³ + x²) = -x³ - x²
f(-x) = (-x)³ + (-x)² = [(-1)(x)]³ + [(-1)(x)]² = (-1)³x³ + (-1)²x²
= -1x³ + 1x² =-x³ + x²
f(-x) ≠ f(x) and f(-x) ≠ -f(x)
y = x³ + x² is not odd and not even
Answer: neither
Answer:
13.567%
Step-by-step explanation:
We solve the above question, using z score formula
z = (x-μ)/σ, where
x is the raw score = 23.1 ounces
μ is the population mean = 22.0 ounces
σ is the population standard deviation = 1.0 ounce
More than = Greater than with the sign = >
Hence, for x > 23.1 ounces
z = 23.1 - 22.0/1.0
= 1.1
Probability value from Z-Table:
P(x<23.1) = 0.86433
P(x>23.1) = 1 - P(x<23.1)
P(x>23.1) = 1 - 0.86433
P(x>23.1) = 0.13567
Converting to percentage
= 0.13567 × 100
= 13.567%
Therefore, the percentage of regulation basketballs that weigh more than 23.1 ounces is 13.567%
Answer:
Area = 
square centimeter
If the circumference of the hub cap would have been smaller, then its radius would have been smaller and subsequently its area would also have been less.
Step-by-step explanation:
As we know the circumference of a circle is 
The radius of the hub cap needs to be devised to determine the area
centimeters
Area of the hub cap = 
Substituting the devised value of r in the above equation, we get -
square centimeter
If the circumference of the hub cap would have been smaller, then its radius would have been smaller and subsequently its area would also have been less.
