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maks197457 [2]
2 years ago
8

Need help on numbers 6, 7, and 8 ill mark brainliest if they are right

Mathematics
1 answer:
mr Goodwill [35]2 years ago
3 0

Answer:

Volume of Triangular Pyramid =29920 cubic inches

volume of the sphere = 113.04 cubic millimeters

(Is this answer helpful :-)

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Can someone pls help me? I’m confused!
OleMash [197]

Answer:

? = 24

Step-by-step explanation:

Pizzas = 3

Because of this, burgers must be 2

2³ = 8

Tacos = 8

8 + 8 + 8 = 24

7 0
3 years ago
Read 2 more answers
Help I am very bad at math I need answers by tomorrow if you can help please do​
d1i1m1o1n [39]

Answer:

Step-by-step explanation:

(a - b)(a +b) = a² - b²

1 - Sin² A = Cos² A

LHS = \frac{1}{1- Sin A} + \frac{1}{1 + Sin A}\\\\= \frac{1*(1 + Sin A)}{(1- Sin A)(1 + Sin A)} + \frac{1*(1- Sin A)}{(1 + Sin A)(1- Sin A)}\\\\= \frac{1 + Sin A+ 1 - Sin A}{1^{2}-  Sin^{2} A}\\\\= \frac{2}{1 - Sin^{2} A}\\\\= \frac{2}{Cos^{2} A}\\\\= 2 Sec^{2} A

2)  Sec² A - Tan² A = 1

LHS = \frac{1}{Sec A - Tan A}\\\\=\frac{1*(Sec A + Tan A)}{(Sec A -  Tan A)(Sec A + Tan A)}\\\\=\frac{Sec A + Tan A}{Sec^{2} A - Tan^{2} A}\\\\=\frac{Sec A + Tan A }{1}\\\\= Sec A + Tan A = RHS\\\\\\

3) LHS  = Cosec² A + Cot² A

             = Cosec² A +  Cosec² A - 1

            = 2Cosec² A - 1   = RHS

4) LHS = \frac{Sec A}{Cos A}- \frac{Tan A}{Cot A}\\\\          = Sec A*\frac{1}{Cos A}-Tan A*\frac{1}{Cot A}\\\\ = Sec A * Sec A - Tan A * Tan A\\\\= Sec^{2} A - Tan^{2} A \\\\= 1

3 0
3 years ago
Help , which segment is congruent to al
svetlana [45]

CI is congruent to AI

Step-by-step explanation:

Congruent means  they are identical, CI and AI are identical

5 0
2 years ago
900 students took 18 buses to the museum. on average, how many students rode each bus?
maks197457 [2]
900/18=50
On average, 50 students rode each bus
Hope this helps!
8 0
3 years ago
Simplify the expression. (x1/6 y1/9)3
harina [27]
Ok, first let's multiply:
3 x 1/6 = 3/6 (simplify:) 1/2

Then multiply again:
3 x 1/9 = 3/9 (simplify:) 1/3

Now the expression is simplified to (1/2x, 1/2y)

Hope this helped! Please comment or DM me if you have anymore questions or don't understand :)
8 0
3 years ago
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