This appears to be about rules of exponents as much as anything. The applicable "definitions, identities, and properties" are
i^0 = 1 . . . . . as is true for any non-zero value to the zero power
i^1 = i . . . . . . as is true for any value to the first power
i^2 = -1 . . . . . from the definition of i
i^3 = -i . . . . . = (i^2)·(i^1) = -1·i = -i
i^n = i^(n mod 4) . . . . . where "n mod 4" is the remainder after division by 4
1. = -3^4·i^(3·2+0+2·4) = -81·i^14 =
812. = i^((3-5)·2+0 = i^-4 =
13. = -2^2·i^(4+2+2+(-1+1+5)·3+0) = -4·i^23 =
4i4. = i^(3+(2+3+4+0+2+5)·2) = i^35 =
-i
It's not a proper square root, but you're looking for a number between 25 and 26 (<span>25.6515106768)</span>
Answer:
-81
Step-by-step explanation:
f(x) = 8x -1
f(-10) = 8(-10) -1
f(-10) = -80-1
f(-10) = -81
2 1/2 cups of milk for each cup of oatmeal
Answer:
Step-by-step explanation:
How to Find Outliers Using the Interquartile Range(IQR)
Step 1: Find the IQR, Q1(25th percentile) and Q3(75th percentile). ...
Step 2: Multiply the IQR you found in Step 1 by 1.5: ...
Step 3: Add the amount you found in Step 2 to Q3 from Step 1: ...
Step 3: Subtract the amount you found in Step 2 from Q1 from Step 1: