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Zina [86]
3 years ago
9

Suppose that the amount of algae in a pond doubles every 6 hours. if the pond initially contains 50 pounds of algae, how much al

gae will be in the pond after 18 hours?
A. 400
B. 10,800
C. 300
D. 600
Mathematics
1 answer:
bulgar [2K]3 years ago
5 0

Answer:

A. 400

Step-by-step explanation:

initially have 50 pounds after 6 hours, doubles to 100. 6 (12 total) more hours 100 doubles to 200. after another 6 (18 hours) 200 doubles to 400.

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Answer: X = 4/61

Step-by-step explanation

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2 years ago
Find the set of outcomes that occur when we flip 3 coins and obtain at least two tails.
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First, I would show all the outcomes possible. To determine the number of the total outcomes, you use the formula: rⁿ, where r is the number of outcomes in 1 flip, and n is the number of lips. Thus, 2³ = 8 outcomes. These outcomes are:

1. HHH
2. TTT
3. HHT
<em>4. HTT</em>
5. HTH
6. THH
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<em>8. THT</em>

From the given outcomes, there are <em>3 outcomes</em> that has at least two tails. These are the ones in bold characters.
5 0
3 years ago
What is the answer to (8x-44)
kodGreya [7K]
Are you solving for x or what
3 0
3 years ago
4 days I have 140 copies of a book, 9 days I only have 50 left. Write an equation where c(t)=my+b where c is number of copies st
alexandr402 [8]

Answer:

c(t)=-18t+212.

Step-by-step explanation:

We have been given that 4 days I have 140 copies of a book, 9 days I only have 50 left. We are asked to write an equation c(t)=my+b, where c is number of copies still on hand and t days being available.

We have two points on line (4,140) and (9,50). Now, we will use these points to find slope as:

m=\frac{140-50}{4-9}

m=\frac{90}{-5}

m=-18

Now, we will use point-slope form of equation y-y_1=m(x-x_1) and substitute m=-18 and coordinates of point (9,50) as:

y-50=-18(x-9)

y-50=-18x+162

y-50+50=-18x+162+50

y=-18x+212

Therefore, our required equation would be c(t)=-18t+212.

5 0
3 years ago
You need 250 mL of a 90% alcohol solution. On hand, you have a 75% alcohol mixture. How much of the 75% alcohol mixture and pure
stich3 [128]

9514 1404 393

Answer:

  • 100 mL of 75% solution
  • 150 mL of pure alcohol

Step-by-step explanation:

Let x represent the quantity (in mL) of pure alcohol needed for the mix. Then the amount of 75% needed is (250-x). The amount of alcohol in the mixture is ...

  1.00x +0.75(250 -x) = 0.90(250)

  0.25x +187.5 = 225 . . simplify

  0.25x = 37.5 . . . . . . . . subtract 187.5

  x = 150 . . . . . . . . . . . . . divide by 0.25

  (250 -x) = 100 . . . . mL of 75% solution

You need 100 mL of the 75% solution and 150 mL of pure alcohol to obtain the desired mixture.

8 0
3 years ago
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