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Jobisdone [24]
4 years ago
10

. Solve for x. Show all work. (10 points) 4(2x + 1) - 3= -3(x – 4) 2. List the 5 steps for solving a problem (5 points) 3. Defin

e Absolute Value (1 point) 4. Name and define the 4 primary symbols you need to know when working with inequalities. (4 points) 5. What are the two types of compound inequalities? Give an example of each?
Mathematics
1 answer:
maksim [4K]4 years ago
6 0
4•(2x+1) 4•2x=8x 4•1=4
8x+4
-3=-3(x-4)
-3•x=-3x
-3•(-4)=12
-3=12-3x
-3=12
X=2

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Answer:

<D=<N

Step-by-step explanation:

Corresponding angle, both in third digit, others are in different digits.

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Cell phone companies estimate that the total number of text messages (t) since the beginning of the month can be modeled by t=40
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The desired number is the difference between the number of messages sent by the 16th day and the number sent by the 9th day:

... n = t(16) - t(9)

... n = (40×√16) - (40×√9)

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A train leaves Philadelphia at 2:00 PM. A second train leaves the same city in the same direction at 4:00 PM. The second train t
polet [3.4K]

Answer: First train speed shall be 42 mi/hr

Second train speed shall be 84 mi/hr

Yes it is the valid answer, it gets annoying when almost everyone enters the wrong answer for a good laugh. Either way, hope this helps! Have a spectacular day.

Step-by-step explanation:

What is the 1st train's head start in miles?

Let +s+ = the speed of the 1st train in mi/hr

From 2PM to 4PM is 2 hrs

+d%5B1%5D+=+s%2A2+

---------------------

Let +d+ = distance the 2nd train travels until

it overtakes the 1st train

From 4PM to 6PM is 2 hrs

Start time when the 2nd train leaves

---------------------

Equation for 1st train:

(1) +d+-+2s+=+s%2A2+

Equation for 2nd train:

(2) +d+=+%28+s%2B42+%29%2A2+

--------------------

Substitute (2) into (1)

(1) +%28+s%2B42+%29%2A2+-+2s+=+s%2A2+

(1) +2s+%2B+84+-+2s+=+2s+

(1) +2s+=+84+

(1) +s+=+42+

and

+s%2B+42+=+42+%2B+42+

+s+%2B+42+=+84+

------------------

The 1st train's speed is 42 mi/hr

The 2nd train's speed is 84 mi/hr

---------------------------

check:

(2) +d+=+%28+s%2B42+%29%2A2+

(2) +d+=84%2A2+

(2) +d+=+168+

and

(1) +d+-+2s+=+s%2A2+

(1) +d+-+2%2A42+=+42%2A2+

(1) +d+=+84+%2B+84+

(1) +d+=+168+

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