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maks197457 [2]
3 years ago
12

Find the equation of the circle whose center and radius are given. center ( 7, -3), radius = √7

Mathematics
1 answer:
arsen [322]3 years ago
7 0

Answer & Step-by-step explanation:

The equation of a circle is...

(x-x1)^2+(y-y1)^2=r^2

So all we have to do is plug in the numbers we are given.

So, the equation of the circle is (x - 7)² + (y + 3)² = √7²

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ExtremeBDS [4]

Answer:

x=\frac{3}{4}+i\frac{\sqrt{7}}{4},\:x=\frac{3}{4}-i\frac{\sqrt{7}}{4}

Step-by-step explanation:

simplify \frac{-3}{x-2} by putting the negative sign on the outside. \frac{2x}{x-1}-\frac{2x-5}{x^2-3x+2}=-\frac{3}{x-2}

find the LCM of the denominators. It is (x-1)(x-2). Multiply by the LCM:

\frac{2x}{x-1}\left(x-1\right)\left(x-2\right)-\frac{2x-5}{x^2-3x+2}\left(x-1\right)\left(x-2\right)=-\frac{3}{x-2}\left(x-1\right)\left(x-2\right)

Simplify:

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solve: x=\frac{3}{4}+i\frac{\sqrt{7}}{4},\:x=\frac{3}{4}-i\frac{\sqrt{7}}{4}

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