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beks73 [17]
2 years ago
12

What is the linear equation of the horizontal line that passes through the point (–3, 4)?show your work

Mathematics
1 answer:
ziro4ka [17]2 years ago
3 0

if the ordered pair (x,y) is (-3, 4), then the othre ordered pair would (0,0)

Then, you find the slope(m).

So, m = <u>y2</u><u> - y1</u>

x2 - x1

if y2 is 4 and y1 is 0

x2 is -3 and y1 is 0

now you subtract to get <u>-</u><u>4</u>

3

So, m= <u>-</u><u>4</u>

3

Then, find the y-intercept

So, y=mx+b and substitute the ordered pair (0,0) into y= mx+b

y=mx+ b

0= <u>-</u><u>4</u>(0) +b

3

0=0+b

-0 -0

b=0

So the equation is y= <u>-</u><u>4</u>x

3

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(3, 50) and (14,303)

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Given the system of equations;

y=23x–19 ....1

x²–y= – 6x–23 ...2

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