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beks73 [17]
2 years ago
12

What is the linear equation of the horizontal line that passes through the point (–3, 4)?show your work

Mathematics
1 answer:
ziro4ka [17]2 years ago
3 0

if the ordered pair (x,y) is (-3, 4), then the othre ordered pair would (0,0)

Then, you find the slope(m).

So, m = <u>y2</u><u> - y1</u>

x2 - x1

if y2 is 4 and y1 is 0

x2 is -3 and y1 is 0

now you subtract to get <u>-</u><u>4</u>

3

So, m= <u>-</u><u>4</u>

3

Then, find the y-intercept

So, y=mx+b and substitute the ordered pair (0,0) into y= mx+b

y=mx+ b

0= <u>-</u><u>4</u>(0) +b

3

0=0+b

-0 -0

b=0

So the equation is y= <u>-</u><u>4</u>x

3

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Answer:

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Step-by-step explanation:

To solve this, we will need to set up a system of equations and get rid of a variable.

-3x - 2y = 54

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From this, we can see that the 'y' variables can be cancelled out if we add the two together. This means that we must add these equations to each other to cancel out the 'y' variables:

-3x - 2y = 54

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Since we have solved for 'x', we can simply plug this value into an equation to find 'y'.

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Using these coordinates, find the slope. (0, -6), (3, -2)
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The slope between the points (0, -6) and (3, -2) will be:

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Step-by-step explanation:

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The slope between the points (0, -6) and (3, -2) will be:

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