For this problem, we can use systems of equations. I will use the variables <em>x </em> (for ice-cream) and <em>y</em> (for soda). We get the system:
2.25x+0.75y=30.00
x+y=18
Putting the second equation in terms of y, we get that y=-x+18. We can substitute this into our first equation.
2.25x+0.75y=30.00
becomes
2.25x+0.75(-x+18)=30
Solving for x, we get that x=11. This satisfies answer B.
However, if you want to check to see if this is correct, you could find y by plugging in your value of x into the first equation, then check to see if your found values satisfy BOTH equations.
2.25(11)+0.75y=30
24.75+0.75y=30
0.75y=5.25
y=7
Then we plug this into both equations to see if they are true.
2.25(11)+0.75(7)=30
24.75+5.25=30
30=30 (This is true)
x+y=18
11+7=18
18=18 (This is true).
Both equations are true, so the value for x and y are correct. We see that only answer B is supported through analyzing your work.
:)
She bought 30 tickets. Just do 7.50 divide 0.25.
Answer:??? sorry i dont know
Step-by-step explanation:
A ratio is a one or more letter term
Answer:
The home would be worth $249000 during the year of 2012.
Step-by-step explanation:
The price of the home in t years after 2004 can be modeled by the following equation:

In which P(0) is the price of the house in 2004 and r is the growth rate.
Since 2003 median home prices in Midvale, UT have been growing exponentially at roughly 4.7 % per year.
This means that 
$172000 in 2004
This means that 
What year would the home be worth $ 249000 ?
t years after 2004.
t is found when P(t) = 249000. So







2004 + 8.05 = 2012
The home would be worth $249000 during the year of 2012.