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Akimi4 [234]
3 years ago
13

kurt swims 575 yards at each swim practice. if he practices monday wensday and friday about how may yards will he swim in a wek

Mathematics
2 answers:
Mashcka [7]3 years ago
8 0
1,725 yards, because 575×3=1,725. Or 575+575+575=1,725
Rom4ik [11]3 years ago
5 0
1725 yards because 575 yards times 3 days
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A scatter plot is made to model the amount of money left to pay on a car loan. The data used for the scatter plot are shown in t
lbvjy [14]

Answer:

"the original amount of the loan"

Step-by-step explanation:

x value would be the time in months and y value would be the loan amount that is left.

The y-intercept is basically the point where x is 0. So, we can say the y-intercept would be when time is 0.

<em>That's basically when the loan started and the y-value represents the full loan amount., which is $22,000.</em>

<em />

The correct answer is third option -- "the original amount of the loan".

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5 0
3 years ago
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Bad White [126]

12% is the percent decrease

95,920 is 88% of 109,000.
x/100 = 95,920/109,000

95,920 x 100 = 9,592,000

9,592,000 / 109,000 = 88

100 - 88 = 12

Since it is 88% of it, it decreased by 12%

5 0
2 years ago
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F(x) = {4x² – 1,<br> x = -2<br> x &gt; -2<br> la<br> -x,<br><br> what is f(0)
beks73 [17]
Yes that answer is accurate
5 0
3 years ago
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Lubov Fominskaja [6]

Answer:

See Below.

Step-by-step explanation:

We are given the isosceles triangle ΔABC. By the definition of isosceles triangles, this means that ∠ABC = ∠ACB.

Segments BO and CO bisects ∠ABC and ∠ACB.

And we want to prove that ΔBOC is an isosceles triangle.

Since BO and CO are the angle bisectors of ∠ABC and ∠ACB, respectively, it means that ∠ABO = ∠CBO and ∠ACO = ∠BCO.

And since ∠ABC = ∠ACB, this implies that:

∠ABO = ∠CBO =∠ACO = ∠BCO.

This is shown in the figure as each angle having only one tick mark, meaning that they are congruent.

So, we know that:

\angle ABC=\angle ACB

∠ABC is the sum of the angles ∠ABO and ∠CBO. Likewise, ∠ACB is the sum of the angles ∠ACO and ∠BCO. Hence:

\angle ABO+\angle CBO =\angle ACO+\angle BCO

Since ∠ABO =∠ACO, by substitution:

\angle ABO+\angle CBO =\angle ABO+\angle BCO

Subtracting ∠ABO from both sides produces:

\angle CBO=\angle BCO

So, we've proven that the two angles are congruent, thereby proving that ΔBOC is indeed an isosceles triangle.

7 0
3 years ago
Read 2 more answers
Tom throws a ball into the air. The ball travels on a parabolic path represented by the equation , where represents the height o
tigry1 [53]

Answer:

2.5 second

Step-by-step explanation:

The equation is missing in the question.

The equation is,  h=-8t^2+40t  , where 'h' is the height and 't' is time measured in second.

Now we know to reach its maximum height, h in t seconds, the derivative of h with respect to time t is given by :

\frac{dh}{dt} =0

Now the differentiating the equation with respect to time t, we get

\frac{dh}{dt}=\frac{d}{dt}(-8t^2+40t)

\frac{dh}{dt}=-16t+40

For maximum height,  \frac{dh}{dt} =0

So, -16t+40=0

 \Rightarrow 16t=40

\Rightarrow t=\frac{40}{16}

\Rightarrrow t = 2.5

Therefore, the ball takes 2.5 seconds time to reach the maximum height.

7 0
3 years ago
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