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3 years ago

kurt swims 575 yards at each swim practice. if he practices monday wensday and friday about how may yards will he swim in a wek

Mathematics

2 answers:

Mashcka [7]3 years ago

8 0

1,725 yards, because 575×3=1,725. Or 575+575+575=1,725

Rom4ik [11]3 years ago

5 0

1725 yards because 575 yards times 3 days

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A scatter plot is made to model the amount of money left to pay on a car loan. The data used for the scatter plot are shown in t

lbvjy [14]

Answer:

"the original amount of the loan"

Step-by-step explanation:

x value would be the time in months and y value would be the loan amount that is left.

The y-intercept is basically the point where x is 0. So, we can say the y-intercept would be when time is 0.

That's basically when the loan started and the y-value represents the full loan amount., which is $22,000.

The correct answer is third option -- "the original amount of the loan".

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Bad White [126]

12% is the percent decrease

95,920 is 88% of 109,000.
x/100 = 95,920/109,000

95,920 x 100 = 9,592,000

9,592,000 / 109,000 = 88

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Since it is 88% of it, it decreased by 12%

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beks73 [17]

Yes that answer is accurate

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Lubov Fominskaja [6]

Answer:

See Below.

Step-by-step explanation:

We are given the isosceles triangle ΔABC. By the definition of isosceles triangles, this means that ∠ABC = ∠ACB.

Segments BO and CO bisects ∠ABC and ∠ACB.

And we want to prove that ΔBOC is an isosceles triangle.

Since BO and CO are the angle bisectors of ∠ABC and ∠ACB, respectively, it means that ∠ABO = ∠CBO and ∠ACO = ∠BCO.

And since ∠ABC = ∠ACB, this implies that:

∠ABO = ∠CBO =∠ACO = ∠BCO.

This is shown in the figure as each angle having only one tick mark, meaning that they are congruent.

So, we know that:

$\angle ABC=\angle ACB$

∠ABC is the sum of the angles ∠ABO and ∠CBO. Likewise, ∠ACB is the sum of the angles ∠ACO and ∠BCO. Hence:

$\angle ABO+\angle CBO =\angle ACO+\angle BCO$

Since ∠ABO =∠ACO, by substitution:

$\angle ABO+\angle CBO =\angle ABO+\angle BCO$

Subtracting ∠ABO from both sides produces:

$\angle CBO=\angle BCO$

So, we've proven that the two angles are congruent, thereby proving that ΔBOC is indeed an isosceles triangle.

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Tom throws a ball into the air. The ball travels on a parabolic path represented by the equation , where represents the height o

tigry1 [53]

Answer:

2.5 second

Step-by-step explanation:

The equation is missing in the question.

The equation is, $h=-8t^2+40t$ , where 'h' is the height and 't' is time measured in second.

Now we know to reach its maximum height, h in t seconds, the derivative of h with respect to time t is given by :

$\frac{dh}{dt} =0$

Now the differentiating the equation with respect to time t, we get

$\frac{dh}{dt}=\frac{d}{dt}(-8t^2+40t)$

$\frac{dh}{dt}=-16t+40$

For maximum height, $\frac{dh}{dt} =0$

So, $-16t+40=0$

$\Rightarrow 16t=40$

$\Rightarrow t=\frac{40}{16}$

$\Rightarrrow t = 2.5$

Therefore, the ball takes 2.5 seconds time to reach the maximum height.

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3 years ago