Ask question

Ask question

All categories

3 years ago

5

The volume of a trapezoidal prism is 24 cubic units. It's height is 6 units, as labeled. What is the area of a trapezoidal base

of this prism?

1 answer:

scZoUnD [109]3 years ago

6 0

Answer:

Area of trapezoidal base = 4 square units.

Step-by-step explanation:

We know that volume of a prism is known as :

$V = B \times h$

where <em>B</em> is Area of Base

and <em>h</em> is Height of prism

NOTE: Formula for Volume of a prism can be generalized as above irrespective of the type of base it has (base can be of type triangle, rectangle, square or trapezoidal etc).

Here, we are given that Base is trapezoidal.

<em>h</em> is 6 units and

Volume <em>V</em> is 24 cubic units.

And we have to find out the value of B.

Putting the above values in above formula:

$24 = B \times 6\\\Rightarrow B = \dfrac{24}{6}\\\Rightarrow B = 4 \text { square units}$

Hence, area of trapezoidal base = 4 square units.

You might be interested in

The student body of 115 students want to elect a president and a vice president. How many different ways can they do that

Hitman42 [59]

The different ways that the students can elect a president and a vice president will be 13110.

<h3>What is probability?</h3>

The chances of an event occurring are defined by probability. Probability has several uses in games, in business to create probability-based forecasts,

Given data;

Total no of students = 115

The total number of ways to elect a president = 115

If one person is elected as the president the total number of ways to elect a president = 114

The different ways that the students can elect a president and a vice president are found as;

⇒ 115 ways × 114 ways

⇒ 13110 ways

Hence the different ways that the students can elect a president and a vice president will be 13110.

To learn more about probability, refer to the link;

brainly.com/question/11234923

#SPJ1

4 0

1 year ago

What is the logical form of:

exis [7]

Basically saying u can divide any number by 2 and 3 but not 4

4 0

2 years ago

Solve the differential. This was in the 2016 VCE Specialist Maths Paper 1 and i'm a bit stuck

Nimfa-mama [501]

$\sqrt{2 - x^{2}} \cdot \frac{dy}{dx} = \frac{1}{2 - y}$
$\frac{dy}{dx} = \frac{1}{(2 - y)\sqrt{2 - x^{2}}}$

Now, isolate the variables, so you can integrate.
$(2 - y)dy = \frac{dx}{\sqrt{2 - x^{2}}}$
$\int (2 - y)\,dy = \int\frac{dx}{\sqrt{2 - x^{2}}}$
$2y - \frac{y^{2}}{2} = sin^{-1}\frac{x}{\sqrt{2}} + \frac{1}{2}C$

$4y - y^{2} = 2sin^{-1}\frac{x}{\sqrt{2}} + C$
$y^{2} - 4y = -2sin^{-1}\frac{x}{\sqrt{2}} - C$
$(y - 2)^{2} - 4 = -2sin^{-1}\frac{x}{\sqrt{2}} - C$
$(y - 2)^{2} = 4 - 2sin^{-1}\frac{x}{\sqrt{2}} - C$

$y - 2 = \pm\sqrt{4 - 2sin^{-1}\frac{x}{\sqrt{2}} - C}$
$y = 2 \pm\sqrt{4 - 2sin^{-1}\frac{x}{\sqrt{2}} - C}$

At x = 1, y = 0.
$0 = 2 \pm\sqrt{4 - 2sin^{-1}\frac{1}{\sqrt{2}} - C}$
$-2 = \pm\sqrt{4 - 2sin^{-1}\frac{1}{\sqrt{2}} - C}$

$4 - 2sin^{-1}\frac{1}{\sqrt{2}} - C > 0$
$\therefore 2 = \sqrt{4 - 2sin^{-1}\frac{1}{\sqrt{2}} - C}$

$4 = 4 - 2sin^{-1}\frac{1}{\sqrt{2}} - C$
$0 = -2sin^{-1}\frac{1}{\sqrt{2}} - C$
$C = -2sin^{-1}\frac{1}{\sqrt{2}} = -2\frac{\pi}{4}$
$C = -\frac{\pi}{2}$

$\therefore y = 2 - \sqrt{4 + \frac{\pi}{2} - 2sin^{-1}\frac{x}{\sqrt{2}}}$

6 0

3 years ago

I need help on question 9.

KengaRu [80]

Answer: C) 40 degrees

Step-by-step explanation:

if the total angle is 70 degrees and part of it is 30 degrees

then the other part is x degrees

30 + x = 70

30 - 30 + x = 70 - 30

x= 40

Hope this helped!

<!> Brainliest is appreciated! <!>

7 0

2 years ago

Read 2 more answers

7. Graph the following:<br> y = x/2 -3

Elodia [21]

Answer:

Step-by-step explanation:

pls mark me brainliest

8 0

3 years ago