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3 years ago

Find an equation of the line that satisfies the given conditions. through (9, 7); perpendicular to the line y = 5

Mathematics

1 answer:

cluponka [151]3 years ago

5 0

The answer would defintley be 69 if you want the right answer.

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Please help me on this

earnstyle [38]

The answer is D because the square root of 3^15 is 2187 square root of 3. Now if you add 3^7 then that gives you 2187. So your answer would be D

6 0

3 years ago

Read 2 more answers

Given that ABCD is a rectangle, find the perimeter of the figure below. Round your answer to the nearest tenth. *

BARSIC [14]

Answer:

ANSWER IS OPTION B 

19.7FT

PERIMETER OF FIG.=2 (L+B)-B + PI*R

=2 (6+3)-3 + 3.14*1.5

=18-3+4.71

=15+4.71

=19.71

=19.7 ft

6 0

3 years ago

WILL MARK BRAINLIST!!! NEED CORRECT ANSWER ASAPPP

wariber [46]

Answer:

c) 11

Step-by-step explanation:

7 0

3 years ago

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Bella is x years old. Jake is 9 years older than Bella. Five times Jake’s age is equal to 300. (a) Write an equation that could

podryga [215]

300 divided by 5= jake
Jakes answer minus 9 is Bella’s age

3 0

3 years ago

A prism with a base area of 8 cm² and a height of 6 cm is dilated by a factor of 54 . What is the volume of the dilated prism? E

Aliun [14]

Question:

A prism with a base area of 8 cm² and a height of 6 cm is dilated by a factor of 5/4 .

What is the volume of the dilated prism?

Enter your answer, as a decimal, in the box.

Answer:

The volume of the dilated prism is $93.75 \ {cm}^{3}$

Explanation:

A prism with a base area of 8 cm² and a height of 6 cm

The volume of the prism can be determined by the formula, $V=Bh$

Volume of the prism is given by

$V=Bh$

$V=(8)(6)$

$V=46\ cm^3$

Thus, the volume of the prism is $46 \ {cm}^{3}$

It is also given that the volume of the dilated prism is dilated by a factor of $\frac{5}{4}$

Hence, the new volume is given by

$Volume = 48(\frac{5}{4} )^3$

$=48(\frac{125}{64} )$

$=48(1.953125)$

$=93.75 \ {cm}^{3}$

Thus, the volume of the dilated prism is $93.75 \ {cm}^{3}$

3 0

3 years ago