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liq [111]
2 years ago
15

Area of shaded segment​

Mathematics
2 answers:
ipn [44]2 years ago
6 0

Answer:

<em>Area Of Shaded Segment =</em>

<u><em>In Pictures</em></u>

Juliette [100K]2 years ago
4 0

Answer:

N/A

Step-by-step explanation:

Which area of shaded segment?

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Help ASAP ! Please explain too
crimeas [40]

The indicated points are (1,1) and (2,3).  Slope is change in y over change in x,

m = (3 - 1)/(2 - 1) = 2/1 = 2

Answer: C) 2

6 0
3 years ago
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what is the formula for slope? ALL i need is the formula and if u cant give it to me than dont answer it.
babunello [35]
Slope= y2-y1 / x2-x1
6 0
3 years ago
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Cual es la forma más simple al efectuar la operación indicada en la expresión (-3) (-12) ?
gulaghasi [49]

Answer:

Cual es la forma más simple al efectuar la operación indicada en la expresión (-3) (-12) ?  this means What is the simplest way to perform the operation indicated in the expression (-3) (-12)?

Step-by-step explanation:

Multiply -3 by -12 and get 36. hope this was helpful.

7 0
2 years ago
In a triangle ABC, if &lt;B = 60° and the ratio of two sides is a: c= 2: square root 3+1, then &lt;A=
slavikrds [6]

Your answer is 75°.

To answer this question you need to use both the cosine rule and the sine rule. First, we need to find the length of side b by using the cosine rule, where a = 2 and c = √3 + 1. Then you substitute these into the equation:

b² = a² + c² - 2×a×c×cos(B)

b² = (2)² + (√3 + 1)² - 2×2×(√3 + 1)×cos(60)

b² = 4 + 4 + 2√3 - (4 - 4√3)×0.5

b² = 8 - 2 = 6

b = √6

Then you use this length in the sine rule, and find the angle:

\frac{sin(A)}{\sqrt{3}+1 } =\frac{sin(60)}{\sqrt{6} }

sin(A) = (√6 + √2)/4

A = 75

I hope this helps! Let me know if you have any questions

7 0
3 years ago
HOW is anybody supposed to find the answer to this pre calc question???? Express the complex number in trigonometric form. -2 Ho
Rama09 [41]
It has to do with the unit circle, I think it is A because it should be 2(0+ (-1)) but I would probably wait for someone to come behind me and explain it better sorry couldn't help more
4 0
3 years ago
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