The x- intercept is where y = 0 on the graph and the y- intercept is where x= 0 on the graph. When X=0, all the terms, except for the constant are equal to zero, thus the y- intercept is the constant. y=10 when x=0. Use the quadratic formula to find the x value where y=0.
x= (-b +or- sqrt(b^2 -4ac))/2a
y=ax^2 +bx +c
The answer for the x- int is imaginary. This happens because 10 is the parabola's minimum value and it never touches the x- axis. y-int is 10
Answer:
see explanation
Step-by-step explanation:
Using the sum/ difference → product formula
cos x - cos y = - 2sin( )sin ( )
sin x - sin y = 2cos ( )sin ( )
Given
(cosA - cosB)² + (sinA - sinB )²
= [ - 2sin()sin( ) ]² + [ 2cos( )sin( ) ]²
= 4sin² ( )sin² ( ) + 4cos² ( )sin² ( )
= 4sin² ( )[ sin² ( ) + cos² ( ) ← sin²x + cos²x = 1
= 4sin² ( ) × 1
= 4sin² ( ) = right side ⇒ proven
She has $18.50 so she needs $39.50.
6.50×3= 19.50
18.50+19.50= 38
5.25×4=21
38+21=59
Maya would have enough money to go on the trip.
Answer:
Step-by-step explanation:
If you plot the directrix and the focus, you can see that the focus is to the left of the directrix. Since a parabola ALWAYS wraps itself around the focus, our parabola opens sideways, to the left to be specific. The formula for the parabola that opens to the left is
We will solve this for x at the end. The negative is out front because it opens to the left. If it opened to the right, it would be positive.
The vertex of a parabola is exactly halfway between the focus and the directrix, so our vertex coordinates h and k are (3, 6). P is defined as the distance between the vertex and the directrix, or the vertex and the focus. Since the vertex is directly between both the directrix and the focus, each distance is the same. P = 1. Filling in what we have now:
which simplifies to
Now we will solve it for x.
and
so
Answer:
1. x=27
2. x=11 or x=-7
3. x=4
4. x=1 or
5. x=12
6. x=11 or x=-1
7. x=8
8. x=3 or x=1
9. or x=-4
10.x=7 or x=1
Step-by-step explanation:
For the first 8, the absolute value portion is just substituted in for x, so we can skip some of the repeated work that would occur in these. For the absolute value problems, there are two solutions each. When you remove an absolute value, you have to add a plus or minus to each side and solve for each.
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