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maw [93]
3 years ago
10

5 meters of wire. How long is the wire in millimeters?

Mathematics
1 answer:
vampirchik [111]3 years ago
4 0
Its 50 millimeters                                       its 50
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Solve the open sentence. 6 < 3b OR 3b + 12 < 9
Travka [436]
6 < 3b or 3b + 12 < 9

2< b Or 3b < -3  You can only change the sign should you multiply or divide the negative number.

<span>2 < b or b < 1  that means b > 2
Hope this helps :)</span>
3 0
3 years ago
You are constructing triangle ABC given the line segments AB and AC and ∠A. The first thing you do is copy segment AC. Next, you
kondaur [170]

Answer:

  C)  Copy AB

Step-by-step explanation:

The general idea is that you copy one segment, then the angle (so you know which direction the other segment goes), then the second segment. Finally, you connect the ends of the segments to complete the triangle.

The given description says you've done the first two parts of this, so you must mark off the length of segment AB in the direction you just constructed. That is, you must ...

  Copy AB.

_____

In the attached figure, the construction did segment AB first, and is about to do segment AC next. The idea is the same. Swap points B and C in your mind to match the description in the problem statement.

7 0
3 years ago
Solve the equation.<br> 7<br> 12 z = 21
scoundrel [369]

Step-by-step explanation:

z= 21/12

divide bothside by 12

shekinan

8 0
3 years ago
27. A tank holds 240litres of water. How much water is in the tank when it is full?
Lera25 [3.4K]

Answer:

The answer would be A) 240 litres. This is because the question itself told us beforehand how much the tank can hold, which is 240.

4 0
3 years ago
The concentration of particles in a suspension is 50 per mL. A 5 mL volume of the suspension is withdrawn. a. What is the probab
kolezko [41]

Answer:

(a) 0.6579

(b) 0.2961

(c) 0.3108

(d) 240

Step-by-step explanation:

The random variable <em>X</em> can be defined as the number of particles in a suspension.

The concentration of particles in a suspension is 50 per ml.

Then in 5 mL volume of the suspension the number of particles will be,

5 × 50 = 250.

The random variable <em>X</em> thus follows a Poisson distribution with parameter, <em>λ</em> = 250.

The Poisson distribution with parameter λ, can be approximated by the Normal distribution, when λ is large say λ > 10.  

The mean of the approximated distribution of X is:

μ = λ  = 250

The standard deviation of the approximated distribution of X is:

σ = √λ  = √250 = 15.8114

Thus, X\sim N(250, 250)

(a)

Compute the probability that the number of particles withdrawn will be between 235 and 265 as follows:

P(235

                             =P(-0.95

Thus, the value of P (235 < <em>X</em> < 265) = 0.6579.

(b)

Compute the probability that the average number of particles per mL in the withdrawn sample is between 48 and 52 as follows:

P(48

                             =P(-0.28

Thus, the value of P(48.

(c)

A 10 mL sample is withdrawn.

Compute the probability that the average number of particles per mL in the withdrawn sample is between 48 and 52 as follows:

P(48

                             =P(-0.40

Thus, the value of P(48.

(d)

Let the sample size be <em>n</em>.

P(48

                             0.95=P(-z

The value of <em>z</em> for this probability is,

<em>z</em> = 1.96

Compute the value of <em>n</em> as follows:

z=\frac{\bar X-\mu}{\sigma/\sqrt{n}}\\\\1.96=\frac{48-50}{15.8114/\sqrt{n}}\\\\n=[\frac{1.96\times 15.8114}{48-50}]^{2}\\\\n=240.1004\\\\n\approx 241

Thus, the sample selected must be of size 240.

5 0
3 years ago
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