The solution to a system of (linear) equations is the point where the graphs intersect. Consider two parallel lines. By definition, two parallel lines never intersect each other, but all pairs of non-parallel lines will eventually intersect. That means they will also have a solution.
Let's consider what makes a line parallel to another line. It basically looks identical, having the same steepness (slope), but the graph is just shifted over. That is, a parallel line would have the same slope and a different y-intercept. For our equation

, or

in slope-intercept form, a parallel line will be of the form

.
That describes the form of a parallel line, which we do not want. Any other line, however, will give a solution to our system, so we merely want a line where the slope does not equal 2.
We can have any equation of the form

.
Answer:
A. reflection across the y-axiss
Step-by-step explanation:
Given:
The locations of the two points are (-4 , 8) and (-4 , -8).
To find:
The relation between two points.
From the given points (-4, 8) and (-4 , -8), it is clear that the y-coordinates are same but the sign of x-coordinates are opposite.
If a figure is reflected across the y-axis, then we change the sign of x-coordinate and the y-coordinates remain same, i.e.,
→
For (-4,8)
→ 
So, it is reflection across the y-axis.
Therefore, the correct option is A.
Answer: 14x + 42
7(2x+4)+14
14x + 28 + 14
<u>14x + 42</u>
Step-by-step explanation: