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svetlana [45]
3 years ago
9

Find the area of this circle. Use 3.14 to approximate . A = ar2 14 ft A = [ ? ] ft?

Mathematics
1 answer:
scoray [572]3 years ago
3 0

Answer:

A =153.86 ft^2

Step-by-step explanation:

First we need to find the radius

f = d/2 = 14/2 = 7

A = pi r^2

A = 3.14 ( 7)^2

A = 3.14 * 49

A =153.86 ft^2

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If it takes 16 yards of material to make 5/2 costumes, how much material will be needed to make 19/2 costumes of that same size?
IRISSAK [1]

yards/costumes:16/(5/2) = X/(19/2)

Cross multiply.

(5/2)x = 152

Multiply both sides by 2/5.

x = 101 1/3 yards

7 0
3 years ago
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monitta

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Step-by-step explanation:

5 0
3 years ago
Which is greater 11/16 or 3/4
Anettt [7]
To compare fractions, we need to have the same denominator
The least common multiple is 16
\frac{11}{16} 
to change \frac{3}{4}, we should multiply the numerator and denominator by 4
\frac{3*4}{4*4} = \frac{12}{16}

\frac{11}{16} < \frac{12}{16}

so basically, \frac{12}{16} is greater than \frac{11}{16}
which means \frac{3}{4} is greater

\frac{3}{4} is greater
6 0
3 years ago
Given the following sets. a = {0, 1, 2, 3} b = {a, b, c, d} c = {0, a, 2, b} find a c.
ipn [44]
I think the answer is 0.
7 0
3 years ago
Suppose that the sitting​ back-to-knee length for a group of adults has a normal distribution with a mean of mu equals 24.4 in.
solong [7]

Answer:

P(X \geq 26.6) = 0.0336, which is greater than 0.01. So a back-to-knee length of 26.6 in. is not significantly high.

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 24.4, \sigma = 1.2

In this problem, a value x is significantly high if:

P(X \geq x) = 0.01

Using these​ criteria, is a​ back-to-knee length of 26.6 in. significantly​ high?

We have to find the probability of the length being 26.6 in or more, which is 1 subtracted by the pvalue of Z when X = 26.6. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{26.6 - 24.4}{1.2}

Z = 1.83

Z = 1.83 has a pvalue of 0.9664.

1 - 0.9664 = 0.0336

P(X \geq 26.6) = 0.0336, which is greater than 0.01. So a back-to-knee length of 26.6 in. is not significantly high.

6 0
3 years ago
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