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3 years ago

Please help me solve this

Mathematics

2 answers:

kicyunya [14]3 years ago

6 0

Answer:

The answer is 700.4 cm.

Step-by-step explanation:

Hope it helped (ik im a bit late but i tried)

Diano4ka-milaya [45]3 years ago

5 0

Answer:

l=700.4 cm

Step-by-step explanation:

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Work out the volume of this prism.

a_sh-v [17]

Answer:

840

Step-by-step explanation:

Lets split the shape in 2 shapes which gives us 2 rectangular prisms

1st shape is the one stcking upward: 12*5*6=360

2nd shape: (we must subtract 5 from 15 because we used that for the other shape and hat wouldn't give us the correct answer) 10*8*6=480

480+360=

840

8 0

3 years ago

Which two tables represent the same function?

topjm [15]

Answer:

The 1st and the 5th tables represent the same function

Step-by-step explanation:

* Lets explain how to solve the problem

- There are five tables of functions, two of them are equal

- To find the two equal function lets find their equations

- The form of the equation of a line whose endpoints are (x1 , y1) and

(x2 , y2) is $\frac{y-y_{1}}{x-x_{1}}=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}$

* Lets make the equation of each table

# (x1 , y1) = (4 , 8) and (x2 , y2) = (6 , 7)

∵ x1 = 4 , x2 = 6 and y1 = 8 , y2 = 7

∴ $\frac{y-8}{x-4}=\frac{7-8}{6-4}$

∴ $\frac{y-8}{x-4}=\frac{-1}{2}$

- By using cross multiplication

∴ 2(y - 8) = -1(x - 4) ⇒ simplify

∴ 2y - 16 = -x + 4 ⇒ add x and 16 for two sides

∴ x + 2y = 20 ⇒ (1)

# (x1 , y1) = (4 , 5) and (x2 , y2) = (6 , 4)

∵ x1 = 4 , x2 = 6 and y1 = 5 , y2 = 4

∴ $\frac{y-5}{x-4}=\frac{4-5}{6-4}$

∴ $\frac{y-5}{x-4}=\frac{-1}{2}$

- By using cross multiplication

∴ 2(y - 5) = -1(x - 4) ⇒ simplify

∴ 2y - 10 = -x + 4 ⇒ add x and 10 for two sides

∴ x + 2y = 14 ⇒ (2)

# (x1 , y1) = (2 , 8) and (x2 , y2) = (8 , 5)

∵ x1 = 2 , x2 = 8 and y1 = 8 , y2 = 5

∴ $\frac{y-8}{x-2}=\frac{5-8}{8-2}$

∴ $\frac{y-8}{x-2}=\frac{-3}{6}=====\frac{y-8}{x-2}=\frac{-1}{2}$

- By using cross multiplication

∴ 2(y - 8) = -1(x - 2) ⇒ simplify

∴ 2y - 16 = -x + 2 ⇒ add x and 16 for two sides

∴ x + 2y = 18 ⇒ (3)

# (x1 , y1) = (2 , 10) and (x2 , y2) = (6 , 14)

∵ x1 = 2 , x2 = 6 and y1 = 10 , y2 = 14

∴ $\frac{y-10}{x-2}=\frac{14-10}{6-2}$

∴ $\frac{y-10}{x-2}=\frac{4}{4}======\frac{y-10}{x-2}=1$

- By using cross multiplication

∴ (y - 10) = (x - 2)

∴ y - 10 = x - 2 ⇒ add 2 and subtract y in the two sides

∴ -8 = x - y ⇒ switch the two sides

∴ x - y = -8 ⇒ (4)

# (x1 , y1) = (2 , 9) and (x2 , y2) = (8 , 6)

∵ x1 = 2 , x2 = 8 and y1 = 9 , y2 = 6

∴ $\frac{y-9}{x-2}=\frac{6-9}{8-2}$

∴ $\frac{y-9}{x-2}=\frac{-3}{6}======\frac{y-9}{x-2}=\frac{-1}{2}$

- By using cross multiplication

∴ 2(y - 9) = -1(x - 2) ⇒ simplify

∴ 2y - 18 = -x + 2 ⇒ add x and 18 for two sides

∴ x + 2y = 20 ⇒ (5)

- Equations (1) and (5) are the same

∴ The 1st and the 5th tables represent the same function

3 0

3 years ago

Write an equation of the line that passes through a pair of points: -5, -2 3, -1

irinina [24]

Answer: option B is correct.

Step-by-step explanation:

The equation of a straight line can be represented in the slope-intercept form, y = mx + c

Where c = intercept

Slope, m =change in value of y on the vertical axis / change in value of x on the horizontal axis represent

change in the value of y = y2 - y1

Change in value of x = x2 -x1

y2 = final value of y

y 1 = initial value of y

x2 = final value of x

x1 = initial value of x

The line passes through (- 5, - 2) and (3, - 1),

y2 = - 1

y1 = - 2

x2 = 3

x1 = - 5

Slope,m = (- 1 - - 2)/(3 - - 5) = 1/8

To determine the intercept, we would substitute x = 3, y = - 1 and

m = 1/8 into y = mx + c. It becomes

- 1 = 1/8 × 3 + c

- 1 = 3/8 + c

c = - 1 - 3/8 = - 11/8

The equation becomes

y = x/8 - 11/8

8 0

2 years ago

Read 2 more answers

The ribbon was 3 1/4 inches wide and had an area of 19 1/2 square inches. What is the length of the ribbon? Please Help Will Giv

miv72 [106K]

Hello!

The formula for finding area is l × w

If the area is 19 ½ inches and it was 3 ¼ inches wide, then the length will be 19 ½ ÷ 3 ¼ (Area ÷ Width)

$19 \frac{1}{2} \div 3 \frac{1}{4}$

Change both to improper fraction

$19 \frac{1}{2} = \frac{39}{2}$

$3 \frac{1}{4} = \frac{13}{4}$

$\frac{39}{2} \div \frac{13}{4}$

Keep 39/2
Change ÷ to ×
Flip 13/4 = 4/13

$\frac{39}{2} \times \frac{4}{13} = \frac{156}{26} = 6$

$\framebox {The length of the ribbon is 6 inches}$

5 0

3 years ago

Read 2 more answers

WILL MARK BRAINLIEST!!! PLEASE ANSWER!!! WRONG ANSWERS JUST FOR POINTS WILL BE REPORTED!!!!!!!!!!!!!!

Alchen [17]

Answer:

where's the question???

Step-by-step explanation:

4 0

2 years ago

Read 2 more answers