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3 years ago

13

Which equation is a function of x?

2 answers:

zysi [14]3 years ago

8 0

I think it x = 5 but I don’t remember much

Zina [86]3 years ago

5 0

X = 5 is the correct answer I’m pretty sure

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How many solutions are there to the system of equations graphed below if the lines are parallel

mash [69]

If a consistent system has an infinite number of solutions, it is dependent . When you graph the equations, both equations represent the same line<span>. If a system has no solution, it is said to be </span>inconsistent<span> . The graphs of the </span>lines<span> do not intersect, so the graphs </span>are parallel<span> and there is no solution.

Sorry, this is a general answer. I could not view the graph below...</span>

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3 years ago

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Andre45 [30]

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3 years ago

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What are the exact solutions of x^2 − 3x − 7 = 0?

bulgar [2K]

<u>Given</u>:

The given equation is $x^{2} -3x-7=0$

We need to determine the exact solutions of the equation.

<u>Exact solution:</u>

The exact solution of the equation can be determined by solving the equation using quadratic formula,

$x=\frac{-b \pm \sqrt{b^2-4ac}}{2a}$

From the equation the values are a = 1, b = -3 and c = -7

Thus, substituting these values in the equation, we get;

$x=\frac{-(-3) \pm \sqrt{3^2-4(1)(-7)}}{2(1)}$

$x=\frac{3 \pm \sqrt{9+28}}{2}$

$x=\frac{3 \pm \sqrt{37}}{2}$

Thus, the exact solutions of the given equation is $x=\frac{3 \pm \sqrt{37}}{2}$

Hence, Option A is the correct answer.

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3 years ago

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11111nata11111 [884]

Answer:

Took the test, answer is C) 17(100)+17(40)+17(4)

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Coefficiants of (2x+y)^4

sattari [20]

By the binomial theorem,

$(2x+y)^4=\displaystyle\sum_{k=0}^4\binom 4k(2x)^{4-k}y^k=\sum_{k=0}^4\binom 4k2^{4-k}x^{4-k}y^k$

where

$\dbinom nk=\dfrac{n!}{k!(n-k)!}$

Then the coefficients of the $x^{4-k}y^k$ terms in the expansion are, in order from $k=0$ to $k=4$ ,

$\dbinom 402^{4-0}=1\cdot2^4=16$

$\dbinom412^{4-1}=4\cdot2^3=32$

$\dbinom422^{4-2}=6\cdot2^2=24$

$\dbinom432^{4-3}=4\cdot2^1=8$

$\dbinom442^{4-4}=1\cdot2^0=1$

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3 years ago