Question

Marine ecologists estimate the reproduction curve for swordfish in a fishing ground to be f(p) = −0.01p2 + 9p, where p and f(p) are in hundreds. Find the population that gives the maximum sustainable yield, and the size of the yield.

Answer 1

Answer:

The population that gives the maximum sustainable yield is 45000 swordfishes.

The maximum sustainable yield is 202500 swordfishes.

Step-by-step explanation:

Let be $f(p) = -0.01\cdot p^{2}+9\cdot p$, the maximum sustainable yield can be found by using first and second derivatives of the given function: (First and Second Derivative Tests)

First Derivative Test

$f'(p) = -0.02\cdot p +9$

Let equalize the resulting expression to zero and solve afterwards:

$-0.02\cdot p + 9 = 0$

$p = 450$

Second Derivative Test

$f''(p) = -0.02$

This means that result on previous part leads to an absolute maximum.

The population that gives the maximum sustainable yield is 45000 swordfishes.

The maximum sustainable yield is:

$f(450) = -0.01\cdot (450)^{2}+9\cdot (450)$

$f(450) =2025$

The maximum sustainable yield is 202500 swordfishes.