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topjm [15]
1 year ago
8

Solve the inequality. Graph your solution. $$ - 5.3 x > 21 |

Mathematics
1 answer:
kobusy [5.1K]1 year ago
4 0

The solution to the inequality - 5.3 + x > 21 is x > 26.3

In mathematics, inequality refers to a relation which makes a non-equal comparison between two numbers or other mathematical expressions. In other words, it is a relationship between two expressions or values that are not equal to each other. It is used generally used to compare two numbers on the number line by their size.

In order to solve the given inequality - 5.3 + x > 21, add 5.3 both sides.

- 5.3 + x + 5.3 > 21 + 5.3

x > 26.3

The solution means that the value of x is greater than 26.3. The solution is graphed on a number line.

Learn more about Inequality:

brainly.com/question/25275758

#SPJ4

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What is 4/6 ÷8/14???????????????
Morgarella [4.7K]

Answer:

7/6

Step-by-step explanation:

4/6 divided by 8/14

4/6 * 14/8

56/48

Simplified: 7/6

6 0
3 years ago
Read 2 more answers
The rabbit population on a small island is observed to be given by the function
Ahat [919]
A.) P(t) = 130t - 0.4t^4 + 1200
The population is maximum when P'(t) = 0
P'(t) = 130 - 1.6t^3 = 0
1.6t^3 = 130
t^3 = 81.25
t = ∛81.25 = 4.3 months.

Maximum population P(t)max = 130(4.3) - 0.4(4.3)^4 + 1200 = 1,622

b.) The rabbit population will disappear when P(t) = 0
P(t) = 130t - 0.4t^4 + 1200 = 0
 t ≈ 8.7 months
5 0
4 years ago
A =5, b = 12 c =?<br><br><br><br> Pls help I don’t know how to do this
nataly862011 [7]

Answer:

: Use the Pythagorean Theorem

{c}^{2}  =  {a}^{2}  +  {b}^{2}

{c}^{2}  =  {5}^{2}  +  {12}^{2}

{c}^{2}  = 25 + 144

{c}^{2}  = 169

c =  + 13

6 0
3 years ago
What is the value of x?<br><br> Enter your answer, as a decimal, in the box.
iragen [17]

Answer:

x = 67.50 ft

Step-by-step explanation:

Consider, ΔMAB and ΔMNP,

∠M = ∠M (Common)

Given AB║NP and let MN as transversal,

∠MAB = ∠MNP (alternate angle)

Also, Given AB║NP and let MP as transversal,

∠MBA = ∠MPN (alternate angle)

Therefore, ΔMAB ≅ ΔMNP (By AAA similarity )

Thus, by CPCT,

\frac{MA}{MN}=\frac{MB}{MP}=\frac{AB}{NP}

consider first two ratios,

\frac{MA}{MN}=\frac{MB}{MP}

Substitute the values, MA = MN - AN = 49.5 ft

\frac{49.5}{71.5}=\frac{x}{97.5}

On solving for x , we get, x = 67.50 ft

Thus, value of x is 67.50 ft


3 0
4 years ago
Read 2 more answers
All 3 questions 3 pictures for find the missing angles, please with reasoning why? 100 points
Katyanochek1 [597]

Answer:

Problem 1)

m\angle DEG = 38^\circ

Problem 2)

m\angle x =140^\circ \text{ and } m\angle y = 49^\circ

Problem 3)

m\angle EDG = 65^\circ

Step-by-step explanation:

Problem 1: ∠DEG

From the diagram, we know that ∠DFG intercepts Arc DG.

Inscribed angles have half the measure of its intercepted arc. Therefore:

\displaystyle \frac{1}{2}m\stackrel{\frown}{DG}=m\angle DFG

We know that m∠DFG = 38°. So:

\displaystyle \frac{1}{2}m\stackrel{\frown}{DG}=38\Rightarrow m\stackrel{\frown}{DG}=76^\circ

∠DEG also intercepts Arc DG. Hence:

\displaystyle m\angle DEG=\frac{1}{2}m\stackrel{\frown}{DG}

We know that Arc DG measures 76°. Hence:

\displaystyle m\angle DEG =\frac{1}{2}\left(76\right)=38^\circ

Alternate Explanation:

Since ∠DEG and ∠DFG intercept the same arc, ∠DEG ≅ DFG. So, m∠DEG = m∠DFG = 38°.

Problem 2: Circle with Centre O

(Let the bottom left corner be A, upper be B, and right be C.)

∠ACB intercepts Arc AC.

Inscribed angles have half the measure of its intercepted arc. Therefore:

\displaystyle \frac{1}{2}m\stackrel{\frown}{AC}=m \angle ACB

Since m∠ACB = 70°:

\displaystyle \frac{1}{2}m\stackrel{\frown}{AC}=70\Rightarrow m\stackrel{\frown}{AC}=140^\circ

∠<em>x</em> is a central angle and also intercepts Arc AC.

The measure of a central angle is equal to its intercepted arc. Thus:

\displaystyle m\angle x =m\stackrel{\frown}{AC}=140^\circ

The sum of the interior angles of a polygon is given by the formula:

(n-2)\cdot 180^\circ

Where <em>n</em> is the number of sides.

Since the inscribed figure is a four-sided polygon, its interior angles must total:

(4-2)\cdot 180^\circ =360^\circ

Therefore:

21+70+y+(360-x)=360

Substitute and solve for <em>y:</em>

91+y+(360-140)=360\Rightarrow y +311=360\Rightarrow m\angle y = 49^\circ

Problem 3: ∠EDG

∠EFG intercepts Arc EDG.

Inscribed angles have half the measure of its intercepted arc. Therefore:

\displaystyle \frac{1}{2}m\stackrel{\frown}{EDG}=m\angle EFG

Since m∠EFG = 115°:

\displaystyle \frac{1}{2}m\stackrel{\frown}{EDG} = 115\Rightarrow m\stackrel{\frown}{EDG} = 230^\circ

A full circle measures 360°. Hence:

m\stackrel{\frown}{EDG}+m\stackrel{\frown}{EFG}=360^\circ

Since we know that Arc EDG measures 230°:

230^\circ + m\stackrel{\frown}{EFG}=360

Solve for Arc EFG:

m\stackrel{\frown}{EFG}=130^\circ

∠EDG intercepts Arc EFG.

Inscribed angles have half the measure of its intercepted arc. Therefore:

\displaystyle m\angle EDG = \frac{1}{2}m\stackrel{\frown}{EFG}

Since we know that Arc EFG measures 130°:

\displaystyle m\angle EDG = \frac{1}{2}(130)=65^\circ

7 0
3 years ago
Read 2 more answers
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