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topjm [15]
1 year ago
8

Solve the inequality. Graph your solution. $$ - 5.3 x > 21 |

Mathematics
1 answer:
kobusy [5.1K]1 year ago
4 0

The solution to the inequality - 5.3 + x > 21 is x > 26.3

In mathematics, inequality refers to a relation which makes a non-equal comparison between two numbers or other mathematical expressions. In other words, it is a relationship between two expressions or values that are not equal to each other. It is used generally used to compare two numbers on the number line by their size.

In order to solve the given inequality - 5.3 + x > 21, add 5.3 both sides.

- 5.3 + x + 5.3 > 21 + 5.3

x > 26.3

The solution means that the value of x is greater than 26.3. The solution is graphed on a number line.

Learn more about Inequality:

brainly.com/question/25275758

#SPJ4

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Two different types of injection-molding machines are used toform plastic parts. A part is considered defective if it hasexcessi
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a) In hypothesis testing the null hypothesis is never accepted. It is rejected or not rejected. In this case, couldn't be rejected, so it is possible that both machines produce the same fraction of defective parts. It is reasonable to conclude that both machines produce the same fraction of defective parts, although this test doesn't conclude this.

b) P-value =  0.143

c) -0.008\leq \pi_1-\pi_2\leq 0.054

Step-by-step explanation:

<em>In this problem we have to do a Test of Differences between Proportions</em>

<em />

The first step is to state the null and alternative hypothesis

H_0: \pi_1-\pi_2=0\\\\H_1:  \pi_1-\pi_2\neq 0

The null hypothesis represents the case where both machines are expected to produce the same amount of defective parts.

The second step is determine the significance level. In this case is α=0.05.

The third step is to calculate the difference in the proportions

p_1-p_2=(15/300)-(8/300)=0.050-0.027=0.023

The fourth step is to estimate the standard deviation of the difference between proportions.

s_{p_1-p_2}=\sqrt{\frac{p(1-p)}{n_1}  +\frac{p(1-p)}{n_2} }}

As n_1=n_2, we can calculate p as p=(p_1+p_2)/2=(0.050+0.027)/2=0.0385.

Then:

s_{p_1-p_2}=\sqrt{\frac{p(1-p)}{n_1}  +\frac{p(1-p)}{n_2} }}\\\\s_{p_1-p_2}=\sqrt{\frac{2*0.0385(1-0.0385)}{300}}=0.0157

The fifth step is to compute p, the probability (or probability value).

z=(p_1-p_2)/s_{p_1-p_2}=0.023/0.0157= 1.465

A z table can be used to find that the two-tailed probability value for a z=1.465 is P(x>|z|)=0.143.

The probability value (P-value) is 0.143. As it is bigger than the significance level (0.05),  the effect is not significant. We can not reject the hypothesis.

To construct a 95% CI we can write:

(p_1-p_2)-z*s_{p_1-p_2}\leq \pi_1-\pi_2\leq (p_1-p_2)+z*s_{p_1-p_2}

For a 95% CI, z=1.96. The estimated standard deviation is the same calcaulated before. Now we can calculate:

(p_1-p_2)-z*s_{p_1-p_2}\leq \pi_1-\pi_2\leq (p_1-p_2)+z*s_{p_1-p_2}\\\\(0.050-0.027)-1.96*0.0157\leq \pi_1-\pi_2\leq (0.050-0.027)+1.96*0.0157\\\\0.023-0.031\leq \pi_1-\pi_2\leq 0.023+0.031\\\\ -0.008\leq \pi_1-\pi_2\leq 0.054

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