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Tanya [424]
3 years ago
14

3x° 45° 12 E The angles are complementary

Mathematics
1 answer:
makvit [3.9K]3 years ago
5 0

Answer:

3

Step-by-step explanation:

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Question 4 (Multiple Choice Worth 5 points)
IgorC [24]
19.95x + 9.95y <== ur answer
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3 years ago
A toy airplane costs $4.84.. It costs 4 times as much as a toy car. What is the cost of the toy car? Show your work.
Elina [12.6K]
Cost of airplane toy = $4.84
let x be the cost of the toy car
cost of airplane toy is 4 times the cost of toy car; it means 
4x = $4.84
x = 4.84 / 4
x = 1.21
Thus, the cost of toy car is $1.21.
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4 years ago
Question 9 of 10
Stells [14]

Answer:

A. The shopper receives a discount now and pays sales tax on the

discounted price of the item. I think, makes most sense

7 0
3 years ago
Read 2 more answers
In a certain Algebra 2 class of 30 students, 14 of them play basketball and 10 of them play baseball. There are 14 students who
Veseljchak [2.6K]

Answer:

In a certain Algebra 2 class of 30 students, 22 of them play basketball and 18 of them play baseball. There are 3 students who play neither sport. What is the probability that a student chosen randomly from the class plays both basketball and baseball?

I know how to calculate the probability of students play both basketball and baseball which is 1330 because 22+18+3=43 and 43−30 will give you the number of students plays both sports.

But how would you find the probability using the formula P(A∩B)=P(A)×p(B)?

Thank you for all of the help.

That formula only works if events A (play basketball) and B (play baseball) are independent, but they are not in this case, since out of the 18 players that play baseball, 13 play basketball, and hence P(A|B)=1318<2230=P(A) (in other words: one who plays basketball is less likely to play basketball as well in comparison to someone who does not play baseball, i.e. playing baseball and playing basketball are negatively (or inversely) correlated)

So: the two events are not independent, and so that formula doesn't work.

Fortunately, a formula that does work (always!) is:

P(A∪B)=P(A)+P(B)−P(A∩B)

Hence:

P(A∩B)=P(A)+P(B)−P(A∪B)=2230+1830−2730=1330

7 0
3 years ago
Lionel computed the average rate of change in the depth of a pool over a two-week interval to be zero. Which statement must be t
gayaneshka [121]

Answer:The pool must have been the same depth at the start of the interval as it was at the end of the interval.

Step-by-step explanation:

The average rate of change is calculated as:

[final value - initial value] / time interval.

Then, the average rate of change does not take into account intermediates values, and you cannot draw any conclusion about such intermediate values.

In the given case you have:

average rate of change in depth = [final depth - initial depth] / 2 weeks.

0 = [final depth - initial depth] / 2 weeks.

⇒ 0 = final depth - initial depth

⇒ final depth = initial depth.

That is why the conclusion is the second statement of the answer choices: the pool must have been the same depth at the start of the interval as it was at the end of the interval.

In between the pool might have been deeper, more shallow, empty or change in any form, since the average rate of change does not tell the full history but only the net change.

4 0
3 years ago
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