What is the possibility that a randomly selected person is on the swim team

Seth is trying to decrease the amount of time he spend watching television this week he spent 41/2 hrs watching television which

Alekssandra [29.7K]

Answer:

Seth watched TV for 6 3/4 hours last week.

Step-by-step explanation:

Let x be the number of hours he watched TV last week.

(2/3)x = 4 1/2 hrs. Solve for x by mult. both sides by (3/2):

(3/2)(2/3)x = (3/2)(9/2)

Then: x = 27/4 hours, or 6 3/4 hours.

Seth watched TV for 6 3/4 hours last week.

7 0

3 years ago

What is 1.83 repeating as a fraction?

maks197457 [2]

The answer to this question would be: 1 5/6

To change a decimal number into fraction, you need to divide the number on the right of decimal point with 1. In this case, the number is 0.83.
This number is hard since .83 doesn't have many factors. To find the answer you can try to multiply the decimal with some number until it close to 1(no decimal left)
0.83* 2= 1.66
0.83* 3= 2.49 ---> close to half, if you find this number, you can try to double it
0.83* 4= 3.32
0.83* 5= 4.15
0.83* 6= 4.98---> close to 1, that means there is high probability that the number can be divided by 6
0.83 would be 4.98/6, but if we assume that the number is 0.8333...... then 0.83 would be 5/6. So, 1.83 would be 1 5/6

4 0

3 years ago

Read 2 more answers

A jet boat is used to take canoers 200 miles upriver to their starting point. As the driver of the jet boat, Jeremy knows that i

aivan3 [116]

200/5 = 40 mph 200/4 = 50 mph Let x be the speed in still waters and y the speed of current. x + y = 50 x - y = 40 ADD 2x = 90 x = 45 mph ANSWER is C) 2) C

8 0

3 years ago

Read 2 more answers

|2-5x|+3<10 how to solve

ivann1987 [24]

1 Simplify — 2 Equation at the end of step 1 : 2 3 1 ((— • x) - ——) - — = 0 5 10 2 Step 2 : 3 Simplify —— 10 Equation at the end of step 2 : 2 3 1 ((— • x) - ——) - — = 0 5 10 2 Step 3 : 2 Simplify — 5 Equation at the end of step 3 : 2 3 1 ((— • x) - ——) - — = 0 5 10 2 Step 4 :Calculating the Least Common Multiple :

4.1 Find the Least Common Multiple

 The left denominator is : 5 

 The right denominator is : 10

Number of times each prime factor
appears in the factorization of: Prime
Factor Left
Denominator Right
Denominator L.C.M = Max
{Left,Right} 51112011 Product of all
Prime Factors 51010

Least Common Multiple:
10

Calculating Multipliers :

4.2 Calculate multipliers for the two fractions

 Denote the Least Common Multiple by L.C.M
 Denote the Left Multiplier by Left_M
 Denote the Right Multiplier by Right_M
 Denote the Left Deniminator by L_Deno
 Denote the Right Multiplier by R_Deno

 Left_M = L.C.M / L_Deno = 2

 Right_M = L.C.M / R_Deno = 1

Making Equivalent Fractions :

4.3 Rewrite the two fractions into equivalent fractions

Two fractions are called equivalent if they have the same numeric value.

For example : 1/2 and 2/4 are equivalent, y/(y+1)2 and (y2+y)/(y+1)3 are equivalent as well.

To calculate equivalent fraction , multiply the Numerator of each fraction, by its respective Multiplier.

L. Mult. • L. Num. 2x • 2 —————————————————— = —————— L.C.M 10 R. Mult. • R. Num. 3 —————————————————— = —— L.C.M 10 Adding fractions that have a common denominator :

4.4 Adding up the two equivalent fractions
Add the two equivalent fractions which now have a common denominator

Combine the numerators together, put the sum or difference over the common denominator then reduce to lowest terms if possible:

2x • 2 - (3) 4x - 3 ———————————— = —————— 10 10 Equation at the end of step 4 : (4x - 3) 1 ———————— - — = 0 10 2 Step 5 :Calculating the Least Common Multiple :

5.1 Find the Least Common Multiple

 The left denominator is : 10 

 The right denominator is : 2

Number of times each prime factor
appears in the factorization of: Prime
Factor Left
Denominator Right
Denominator L.C.M = Max
{Left,Right} 21115101 Product of all
Prime Factors 10210

Least Common Multiple:
10

Calculating Multipliers :

5.2 Calculate multipliers for the two fractions

 Denote the Least Common Multiple by L.C.M
 Denote the Left Multiplier by Left_M
 Denote the Right Multiplier by Right_M
 Denote the Left Deniminator by L_Deno
 Denote the Right Multiplier by R_Deno

 Left_M = L.C.M / L_Deno = 1

 Right_M = L.C.M / R_Deno = 5

Making Equivalent Fractions :

5.3 Rewrite the two fractions into equivalent fractions

L. Mult. • L. Num. (4x-3) —————————————————— = —————— L.C.M 10 R. Mult. • R. Num. 5 —————————————————— = —— L.C.M 10 Adding fractions that have a common denominator :

5.4 Adding up the two equivalent fractions

(4x-3) - (5) 4x - 8 ———————————— = —————— 10 10 Step 6 :Pulling out like terms :

6.1 Pull out like factors :

4x - 8 = 4 • (x - 2)

Equation at the end of step 6 : 4 • (x - 2) ——————————— = 0 10 Step 7 :When a fraction equals zero : 7.1 When a fraction equals zero ...

Where a fraction equals zero, its numerator, the part which is above the fraction line, must equal zero.

Now,to get rid of the denominator, Tiger multiplys both sides of the equation by the denominator.

Here's how:

4•(x-2) ——————— • 10 = 0 • 10 10

Now, on the left hand side, the 10 cancels out the denominator, while, on the right hand side, zero times anything is still zero.

The equation now takes the shape :
4 • (x-2) = 0

Equations which are never true :

7.2 Solve : 4 = 0

This equation has no solution.
 A a non-zero constant never equals zero.

Solving a Single Variable Equation :

7.3 Solve : x-2 = 0

Add 2 to both sides of the equation :
 x = 2

One solution was found : x = 2

4 0

3 years ago

The basic price for an annual dental checkup and cleaning is $50. If the dentist finds any cavities in there will be an addition

Slav-nsk [51]

Answer:

100n+50

Step-by-step explanation:

the dentist charges $100 dollars per cavity found. Per indicates multiplication. Since there is an additional fee, we add $50 to the $100n, which will make the expression

$100n+50

8 0

3 years ago