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2 years ago

I need some help please

Mathematics

2 answers:

Travka [436]2 years ago

7 0

Answer:

ofn

Step-by-step explanation:

DiKsa [7]2 years ago

3 0

Answer:

Step-by-step explanation:

Since there are 44 average people out of 80. We can do this,

Total students : 600

Checked: 80

Average: 44

Number of averaged throughout the school: 600/80 * 44

l: 7.5 * 44

Thus it is: 330 average students

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Solve the system using substitution <br> y=8-x <br> 7=2-y

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To find y just put 13 where x was in the first equation. Y=8-13.
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1 year ago

-1 2/3 / (-2 1/5)<br> solve this for me please &&' thank you

dangina [55]

Start by putting into improper fractions.
- 1 2/3 = - 5/3
- 2 1/5 = - 11/5

Now stack the fractions like this.

$\frac{ \frac{-5}{3} }{ \frac{-11}{5} }$

Here's the key part (or one of them). Cancel the minus signs. Since there are 2 of them they become a plus.

$\frac{ \frac{5}{3} } { \frac{11}{5} }$

Now invert the 11/5. That means turn it upside down. Put the 5 in the numerator and 11 in the denominator. Multiply by it by the top fraction.

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2 years ago

Keegan is printing and selling his original design on t-shirts. He has concluded that for x shirts, in thousands sold his total

Advocard [28]

Complete question is;

Keegan is printing and selling his original design on t-shirts. He has concluded that for x shirts, in thousands sold his total profits will be p(x) = -x³ + 4x² + x dollars, in thousands will be earned. How many t-shirts (rounded to the nearest whole number) should he print in order to make maximum profits? What will his profits rounded to the nearest whole dollar be if he prints that number of shirts?

Answer:

Number of t-shirts to make maximum profit = 2790 shirts

Maximum profit = $12,209

Step-by-step explanation:

From the question, we are given that the profit function is;

p(x) = -x³ + 4x² + x

For the maximum value of the profit function,

(dp/dx) = 0 and (d²p/dx²) < 0

Since, p(x) = -x³ + 4x² + x

Then,

(dp/dx) = -3x² + 8x + 1

at maximum point (dp/dx) = 0, thus;

-3x² + 8x + 1 = 0

Solving this using quadratic formula, the roots are;

x = -0.12 or 2.79

Also, (d²p/dx²) = -6x + 8

Now, let's put the roots of x into -6x + 8 and check for maximum value conditon;

at x = -0.12

(d²p/dx²) = -6(0.12) + 8 = 7.28 > 0

At x = 2.79

(d²p/dx²) = -6(2.79) + 8 = -8.74 < 0

Maximum has to be d²p/dx² < 0

So, the one that meets the condition is -8.74 < 0 at x = 2.79

Thus, the maximum of the profit function exists when the number of shirts, x = 2.79 (in thousands) = 2790

Now, the maximum profits that corresponds to this number of t-shirts of 2.79(in thousands) is obtained by putting 2.79 for x in the profit function;

So,

p(2.79) = -(2.79)³ + 4(2.79²) + 2.79

p(x) = -21.7176 + 31.1364 + 2.79

p(x) = 12.2088 (in thousand dollars) ≈ $12,209

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2 years ago