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erma4kov [3.2K]
3 years ago
5

Help please someone

Mathematics
2 answers:
Ksju [112]3 years ago
6 0
2.5 should be correct?
Zinaida [17]3 years ago
4 0
Point d is (2.5, -1.5)
x = 2.5
y = -1.5
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What is the value of y?
solong [7]
Sum of interior angles in a triangle = 180
so
2y + y+10 + 50 = 180
3y + 60 = 180
3y = 120
  y = 40

Answer is A. 40
8 0
3 years ago
-3/5, 6/5, -12/5 <br>What is the next term of the geometric sequence ?
raketka [301]

ANSWER:

24/5

STEP-BY-STEP EXPLANATION:

We have the following geometric sequence:

s=-\frac{3}{5},\frac{6}{5},\frac{-12}{5}

To know the following term, we must know the common ratio, like this:

\begin{gathered} r=\frac{-\frac{12}{5}}{\frac{6}{5}}=-2 \\ r=\frac{\frac{6}{5}}{-\frac{3}{5}}=-2 \end{gathered}

Therefore, the following term should be:

-\frac{12}{5}\cdot-2=\frac{24}{5}

8 0
1 year ago
360 miles in 6 hours
elena-14-01-66 [18.8K]
Just divide 360 and 6 and what ever your answer is you add 1 at the bottom for example if your answer is 12 you write your answer like this 12/1
4 0
3 years ago
Read 2 more answers
How do I solve this
Elza [17]

the picture is blurry

8 0
3 years ago
Read 2 more answers
Maria throws a softball straight up into the air with an initial velocity of 50 ft/sec. The ball leaves her hand when it is exac
Nataly_w [17]

Answer:

The equation that models the situation is s_{f} = 4+\frac{v_{f}^{2}-2500}{64.348}.

Step-by-step explanation:

Let suppose that effects from air friction and Earth's rotation can be neglected, so that the softball can be modelled experiment a free fall, that is, an uniform accelerated motion due to gravity. From we know the initial velocity and position of the position and we can determine the final position of the ball as a function of the final velocity:

v_{f}^{2} = v_{o}^{2}+2\cdot a \cdot (s_{f}-s_{o}) (1)

Where:

s_{o}, s_{f} - Initial and final position of the softball, measured in feet.

a - Acceleration, measured in meters per square second.

v_{o}, v_{f} - Initial and final velocities of the softball, measured in feet per second.

If we know that v_{o} = 50\,\frac{ft}{s}, a = -32.174\,\frac{m}{s^{2}} and s_{o} = 4\,ft, then the equation that models the situation is:

v_{f}^{2} = 2500-64.348\cdot (s_{f}-4)

Then, we clear the final position of the softball:

-\frac{v_{f}^{2}-2500}{-64.348} = s_{f}-4

s_{f} = 4+\frac{v_{f}^{2}-2500}{64.348}

The equation that models the situation is s_{f} = 4+\frac{v_{f}^{2}-2500}{64.348}.

8 0
2 years ago
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