Answer:
it's quadratic
Step-by-step explanation:
sorry i answered late but i hope this helps other people
To start, you know that this question is asking for the surface area of one of the cylinders, and the formula to finding the surface area of a cylinder is A=2πrh+2<span>πr^2.
Now, to find the surface area, you first need to figure out the height of the plastic cylinder and its radius.
Since you know that the diameter (twice the radius) of the cylinder is equivalent to 4 marbles, and each marble has a diameter of 2 cm, the diameter of the cylinder would be 8 cm. Then, to find its radius, you divide by 2, so its radius is 4.
Now, since you know that the height of the cylinder is 10 marbles, you multiply 10 by 2 to get that the height is 20 cm tall.
Since you now have the values of the height and the radius, plug the values into the surface area of a cylinder formula (r is radius and h is height).
</span>A=2π(4)(20)+2π(4)^2.
<span>Assuming that pi is 3.14, when you simplify this using PEMDAS, you get
502.4+100.48 which then simplifies to 602.88, the area of the plastic to make one cylinder.
</span>
Answer:
-7
Step-by-step explanation:
-7 + 5 = -2
Can u mark me brainly pleasee???
Answer:
midpoint m= <u>(</u><u>x1 </u><u>+</u><u>x2</u> , <u>y1 </u><u>+</u><u> </u><u>y2</u><u>)</u>
2. 2
Step-by-step explanation:
M =(<u>0</u><u>+</u><u>2</u><u>. </u>, <u>0</u><u>+</u><u>2</u><u>)</u>
2. 2
M=(1,1)
Check the picture below.
so, let's notice, is really just a 2x20 rectangle with a quarter of a semicircle with a radius of 11.
![\bf \stackrel{\textit{area of a circle}}{A=\pi r^2}~~ \implies A=\pi 11^2\implies A=121\pi \implies \stackrel{\textit{one quarter of that}}{\boxed{A=\cfrac{121\pi }{4}}} \\\\[-0.35em] ~\dotfill\\\\ \stackrel{\underline{\textit{area of the figure}}}{\stackrel{\textit{rectangle's area}}{(2\cdot 20)}+\stackrel{\textit{circle's quart's area}}{\cfrac{121\pi }{4}}\qquad \approx \qquad 135.03\implies \stackrel{\textit{rounded up}}{135}}](https://tex.z-dn.net/?f=%5Cbf%20%5Cstackrel%7B%5Ctextit%7Barea%20of%20a%20circle%7D%7D%7BA%3D%5Cpi%20r%5E2%7D~~%20%5Cimplies%20A%3D%5Cpi%2011%5E2%5Cimplies%20A%3D121%5Cpi%20%5Cimplies%20%5Cstackrel%7B%5Ctextit%7Bone%20quarter%20of%20that%7D%7D%7B%5Cboxed%7BA%3D%5Ccfrac%7B121%5Cpi%20%7D%7B4%7D%7D%7D%20%5C%5C%5C%5C%5B-0.35em%5D%20~%5Cdotfill%5C%5C%5C%5C%20%5Cstackrel%7B%5Cunderline%7B%5Ctextit%7Barea%20of%20the%20figure%7D%7D%7D%7B%5Cstackrel%7B%5Ctextit%7Brectangle%27s%20area%7D%7D%7B%282%5Ccdot%2020%29%7D%2B%5Cstackrel%7B%5Ctextit%7Bcircle%27s%20quart%27s%20area%7D%7D%7B%5Ccfrac%7B121%5Cpi%20%7D%7B4%7D%7D%5Cqquad%20%5Capprox%20%5Cqquad%20135.03%5Cimplies%20%5Cstackrel%7B%5Ctextit%7Brounded%20up%7D%7D%7B135%7D%7D)
