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3 years ago

9

Simplify the product –8(–9) A.71 B.74 C.72 D.70

2 answers:

Fittoniya [83]3 years ago

5 0

Answer:

the answer is 72....

- × - = +

lesya [120]3 years ago

5 0

The answer for your question would be C.

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Let |u| = 10 at an angle of 45° and |v| = 13 at an angle of 150°, and w = u + v. What is the magnitude and direction angle of w?

mixer [17]

Given:

$|u|=10$ at an angle of 45°.

$|v|=13$ at an angle of 150°.

$w=u+v$

To find:

Magnitude and direction angle of w.

Solution:

We have,

$w=u+v$

$\theta = 45^\circ, \phi = 150^\circ$

Now,

$u_x=|u|\cos \theta=10\cos 45^\circ=7.071$

$u_y=|u|\sin \theta=u_y=10\sin 45^\circ=7.071$

$v_x=|v|\cos \phi=13\cos 150^\circ=-11.25833$

$v_y=|v|\sin \phi=u_y=13\sin 150^\circ=6.5$

Using these information, we get

$R_x=u_x+v_x=7.071-11.25833=-4.18733$

$R_y=u_y+v_y=7.071+6.5=13.571$

$\text{Direction angle}=\tan^{-1}(\dfrac{R_y}{R_x})$

$\text{Direction angle}=\tan^{-1}(\dfrac{13.571}{-4.18733})$

$\text{Direction angle}=-72.8239$

$\text{Direction angle}=107.1476$

$\text{Direction angle}\approx 107.1$

Now,

$|w|=\sqrt{(|u|\cos \theta +|v|\cos \phi)^2+(|u|\sin \theta +|v|\sin \phi)^2}$

$|w|=\sqrt{(10\cos(45)+13\cos 150)^2+(10\sin(45)+13\sin 150)^2}$

$|w|=\sqrt{(10(\dfrac{1}{\sqrt{2}})+13(-\dfrac{\sqrt{3}}{2}))^2+(10(\dfrac{1}{\sqrt{2}})+13(\dfrac{1}{2}))^2}$

$|w|=14.20236$

$|w|\approx 14.20236$

Therefore, the correct option is D.

4 0

3 years ago

Read 2 more answers

How many significant figures are in the measurement 1.050 L

Lostsunrise [7]

The are four significant figures.

7 0

4 years ago

At the beginning of the week the balance in your bank account was $298.72. During the week you made a deposit of $425.69. You al

Nastasia [14]

425.69+298.72=724.41

29.72+135.47+208.28=373.47

724.41-373.47=350.94

350.94-5=345.94

The answer is c

7 0

4 years ago

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What is the Simplified form of √46/192

Lorico [155]

Answer:

(√138)/24

Step-by-step explanation:

$\displaystyle\sqrt{\frac{46}{192}}=\sqrt{\frac{46\cdot 3}{192\cdot 3}}=\sqrt{\frac{138}{24^2}}=\frac{\sqrt{138}}{24}$

8 0

3 years ago

For what values of x is x^2 + 2x = 24 true?

maw [93]

Answer:

$x = -6, x = 4$

Step-by-step explanation:

<u>Step 1: Factor</u>

<em>Subtract 24 from both sides</em>

$x^2 + 2x- 24 = 24 - 24$

$x^2 + 2x - 24 = 0$

<em>Make two different x's</em>

$x^2 + 2x - 24 = 0$

$x^2 + 6x - 4x - 24 = 0$

<em>Make two different parenthesis</em>

$x^2 + 6x - 4x - 24 = 0$

$(x + 6)(x - 4) = 0$

<em>Step 2: Solve for x in both equations</em>

$x + 6 = 0$

$x + 6 - 6 = 0- 6$

$x = -6$

$x - 4 = 0$

$x - 4 + 4 = 0 + 4$

$x = 4$

Answer: $x = -6, x = 4$

6 0

3 years ago