1. Let's solve your equation step-by-step.
<span><span><span>4x</span>+5</span>=<span>6x
</span></span>Step 1: Subtract 6x from both sides.
<span><span><span><span>4x</span>+5</span>−<span>6x</span></span>=<span><span>6x</span>−<span>6x
</span></span></span><span><span><span>−<span>2x</span></span>+5</span>=0
</span>Step 2: Subtract 5 from both sides.
<span><span><span><span>−<span>2x</span></span>+5</span>−5</span>=<span>0−5
</span></span><span><span>−<span>2x</span></span>=<span>−5
</span></span>Step 3: Divide both sides by -2.
<span><span><span>−<span>2x/</span></span><span>−2 </span></span>=<span><span>−5/</span><span>−2
</span></span></span><span><span>
</span></span>Answer:<span>x=<span>5/<span>2</span></span></span>
Answer:
147+25=172
Step-by-step explanation:
Have a nice day!
Brainliest me pls
Answer: 3.6
Step-by-step explanation:
½bh = 6.12
½ × 3.4 × b = 6.12
b = 6.12/ 1.7
Answer:
Except k=7, any real number for k would cause the system of equations to have no solution.
Step-by-step explanation:
In general a system of equations can be represented as ax+by=c and dx+ey=f. In order this system of equations to have NO SOLUTIONS a/d=b/a≠c/f. In our example a=6, b=4, c=14, d=3, e=2 and f=k. To apply the formula above, 6/3=4/2≠14/k. Hence k≠7. It can be concluded that except k=7, any real number for k would cause the system of equations to have no solutions.
Just for information, if k=7 the system will have infinitely many solutions.
