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3 years ago

8

Edgar accumulated $11,000 in credit card debt. If the interest rate is 30% per year and he does not make any payments for 3 year

s, how much will he owe on this debt in 3 years by compounding continuously?

2 answers:

Gennadij [26K]3 years ago

8 0

Answer:

= 1.38778e-141 which makes interest a large amount 139 million and 108 hundred thousand and fourhundred and four.

Step-by-step explanation:

The equation is A= P 1+ r/n ^nt

So we input for A = (11000) x 1.30/11000 ^ 36 x 3

= 1.38778e-141 which makes interest a large amount 139 million and 108 hundred thousand and fourhundred and four.

The formula used in the compound interest calculator is A = P(1+r/n)(nt)

A = the future value of the investment

P = the principal investment amount

r = the interest rate (decimal)

n = the number of times that interest is compounded per period

t = the number of periods the money is invested for

Year Year Deposits Year Interest Total Deposits Total Interest Balance

1 $0.00 $245,278.94 $11,000.00 $245,278.94 - $256,278.94

2 $0.00 $5,714,529.54 $11,000.00 $5,959,808.47 - $5,970,808.47

3 $0.00 $133,137,595.61 $11,000.00 $139,097,404.08-$139,108,404.08

Alex17521 [72]3 years ago

5 0

Answer:

$27,055.63

Step-by-step explanation:

The formula for continuously compounded interest is:

$F = Pe^{rt}$

where

F = future value

P = current principal value

r = annual interest rate as a decimal

t = time in years

In this problem, we are looking for F. We are given

P = $11,00

r = 30% = 0.3

t = 3

We use the formula to find F.

$F = $11000e^{0.3 \times 3}$

$F = $11000e^{0.9}$

$F = $11000(2.459603)$

$F = $27055.63$

Answer: In 3 years, he will owe $27,055.63

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Answer:

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Step-by-step explanation:

Let's take it one number at a time.

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$12(-\frac{1}{2})^{2}=3$

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36x - 9 = 9(4x - 1)

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