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ICE Princess25 [194]
3 years ago
6

Find the volume of the shape

Mathematics
2 answers:
Kamila [148]3 years ago
7 0

Answer:

471 units³

Step-by-step explanation:

Volume = \pir²h

Volume = 3.14 × 5 ×5 × 6

Volume = 471 units³

galben [10]3 years ago
6 0

Answer:

471units^{2}

Step-by-step explanation:

Volume for a Cylinder is πr2h

Plug in the numbers to the equation

3.14 (5^{2}) (6) = 471

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Eagle Outfitters is a chain of stores specializing in outdoor apparel and camping gear. They are considering a promotion that in
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Answer:

a) <u>Alternative hypothesis:</u> the use of the coupons is isgnificantly higher than 10%.

<u>Null hypothesis:</u> the use of the coupons is not significantly higher than 10%.

The null and alternative hypothesis can be written as:

H_0: \pi=0.1\\\\H_a:\pi>0.1

b) Point estimate p=0.13

c) At a significance level of 0.05, there is not enough evidence to support the claim that the proportion of coupons use is significantly higher than 10%.

Eagle should not go national with the  promotion as there is no evidence it has been succesful.

Step-by-step explanation:

<em>The question is incomplete.</em>

<em>The sample data shows that x=13 out of n=100 use the coupons.</em>

This is a hypothesis test for a proportion.

The claim is that the proportion of coupons use is significantly higher than 10%.

Then, the null and alternative hypothesis are:

H_0: \pi=0.1\\\\H_a:\pi>0.1

The significance level is 0.05.

The sample has a size n=100.

The point estimate for the population proportion is the sample proportion and has a value of p=0.13.

p=X/n=13/100=0.13

The standard error of the proportion is:

\sigma_p=\sqrt{\dfrac{\pi(1-\pi)}{n}}=\sqrt{\dfrac{0.1*0.9}{100}}\\\\\\ \sigma_p=\sqrt{0.0009}=0.03

Then, we can calculate the z-statistic as:

z=\dfrac{p-\pi-0.5/n}{\sigma_p}=\dfrac{0.13-0.1-0.5/100}{0.03}=\dfrac{0.025}{0.03}=0.833

This test is a right-tailed test, so the P-value for this test is calculated as:

\text{P-value}=P(z>0.833)=0.202

As the P-value (0.202) is greater than the significance level (0.05), the effect is  not significant.

The null hypothesis failed to be rejected.

At a significance level of 0.05, there is not enough evidence to support the claim that the proportion of coupons use is significantly higher than 10%.

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Nicole is running for school president her poster is 3 feet by 2 feet. She liked it so much that she reproduced it on little rec
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Answer:

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Answer:

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= -2.

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