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2 years ago

Which of the following is a ray shown in the drawing?

Mathematics

1 answer:

slavikrds [6]2 years ago

4 0

Answer:

So to get the answer we need to find both of the rays. So first we need to find the end points for the horizontal one. That would be D and E for the horizontal. Those are points, do the same for the diagonal one. AC would be it. AC and DE would be the answer

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The curves y = √x and y=(2-x) and the Cartesian axes form two distinct regions in the first quadrant. Find the volumes of rotati

makkiz [27]

Answer:

Step-by-step explanation:

If you graph there would be two different regions. The first one would be

$y = \sqrt{x} \,\,\,\,, 0\leq x \leq 1 \\$

And the second one would be

$y = 2-x \,\,\,\,\,, 1 \leq x \leq 2$ .

If you rotate the first region around the "y" axis you get that

$A_1 = 2\pi \int\limits_{0}^{1} x\sqrt{x} dx = \frac{4\pi}{5} = 2.51$

And if you rotate the second region around the "y" axis you get that

$A_2 = 2\pi \int\limits_{1}^{2} x(2-x) dx = \frac{4\pi}{3} = 4.188$

And the sum would be 2.51+4.188 = 6.698

If you revolve just the outer curve you get

If you rotate the first region around the x axis you get that

$A_1 =\pi \int\limits_{0}^{1} ( \sqrt{x})^2 dx = \frac{\pi}{2} = 1.5708$

And if you rotate the second region around the x axis you get that

$A_2 = \pi \int\limits_{1}^{2} (2-x)^2 dx = \frac{\pi}{3} = 1.0472$

And the sum would be 1.5708+1.0472 = 2.618

7 0

3 years ago

Which one is it? Please answer thank u

Anestetic [448]

Answer: C

Step-by-step explanation:

3(x+4y-2)

3x+12y-6

8 0

3 years ago

How do you solve this?

masha68 [24]

Here's what i found online:

a/3+4=6

We simplify the equation to the form, which is simple to understand
a/3+4=6

Simplifying:
 + 0.333333333333a+4=6

We move all terms containing a to the left and all other terms to the right.
 + 0.333333333333a=+6-4

We simplify left and right side of the equation.
 + 0.333333333333a=+2

We divide both sides of the equation by 0.333333333333 to get a.
a=6

Hope this helped :-)

4 0

3 years ago

Help I am being timed

Levart [38]

Answer:

Let us say x is a real number and z = a + ib is complex

|x| > 0

|z| = |a + ib| = square-root (a^2 + b^2)

Step-by-step explanation:

|x| > 0 the absolute value of a real number is a nonnegative real number

The |a + ib| = square-root of the sum of the squares of the real components of the complex number

3 0