Answer:
Step-by-step explanation:
The first thing you want to do is to factor in any quadratic equation.
So, -10(x^2-25)
Now, we see this is a special case, whenever we see a equation in this case, x^2 - b^2, we factor it to this (x+b)(x-b)
So, -10(x+5)(x-5)
x = -5 and x = 5
Answer:
θ = π<em>n</em>
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Step-by-step explanation:
Answer:
![x_{1} =-14\\\\x_{2} =6](https://tex.z-dn.net/?f=x_%7B1%7D%20%3D-14%5C%5C%5C%5Cx_%7B2%7D%20%3D6)
Step-by-step explanation:
![x^{2} +8x-84=0\\\\x=\dfrac{-b \pm \sqrt{b^{2}-4ac } }{2a} \\\\a=1; \: \: b=8; \: \: c=-84\\\\x=\dfrac{-8 \pm \sqrt{8^{2}-4 \cdot 1 \cdot (-84) } }{2 \cdot 1}=\dfrac{-8 \pm \sqrt{400 } }{2}=\dfrac{-8 \pm20}{2} =-4 \pm 10\\\\x_{1} =-14\\\\x_{2} =6](https://tex.z-dn.net/?f=x%5E%7B2%7D%20%2B8x-84%3D0%5C%5C%5C%5Cx%3D%5Cdfrac%7B-b%20%5Cpm%20%5Csqrt%7Bb%5E%7B2%7D-4ac%20%7D%20%7D%7B2a%7D%20%5C%5C%5C%5Ca%3D1%3B%20%5C%3A%20%5C%3A%20b%3D8%3B%20%5C%3A%20%5C%3A%20c%3D-84%5C%5C%5C%5Cx%3D%5Cdfrac%7B-8%20%5Cpm%20%5Csqrt%7B8%5E%7B2%7D-4%20%5Ccdot%201%20%5Ccdot%20%28-84%29%20%7D%20%7D%7B2%20%5Ccdot%201%7D%3D%5Cdfrac%7B-8%20%5Cpm%20%5Csqrt%7B400%20%7D%20%7D%7B2%7D%3D%5Cdfrac%7B-8%20%5Cpm20%7D%7B2%7D%20%3D-4%20%5Cpm%2010%5C%5C%5C%5Cx_%7B1%7D%20%3D-14%5C%5C%5C%5Cx_%7B2%7D%20%3D6)
<h2><u>Q</u><u>u</u><u>e</u><u>s</u><u>t</u><u>i</u><u>o</u><u>n</u>:-</h2>
The perimeter of a square is 52 m. What is the area of the square ?
<h2><u>S</u><u>o</u><u>l</u><u>u</u><u>t</u><u>i</u><u>o</u><u>n</u>:-</h2>
Perimeter of a square = 52 m
4 × side = 52
side =
side = 13
So, area of square = (side)² = (13)² = 169 sq m.
<h3>The area of the square is <u>1</u><u>6</u><u>9</u><u> </u><u>s</u><u>q</u><u> </u><u>m</u>. [Answer]</h3>
b= 63 and that is your answer