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Lerok [7]
3 years ago
12

6/3 + 7/12 I really need help with this

Mathematics
2 answers:
Lina20 [59]3 years ago
8 0
11/2 and the alternate form is 5 1/2 but just put 11/2
inn [45]3 years ago
4 0

The answer is 2 7/12

please see the attached picture for full solution

Hope it helps

Good luck on your assignment..

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How many cubic inches of water will the aquarium hold
Nostrana [21]

Answer:

about 1,620 cubic inches

Hope that was helpful.Thank you!

8 0
3 years ago
9 in. 2 in. 5 in 2 in. 2 in 5 in. 2 in.​
Scilla [17]

Answer:

3 in because of the grammit

3 0
3 years ago
Evaluate the function for the given value.<br> If f(x) = -3x2 – 8, then f(-4)= ?
Ganezh [65]

Answer:

The answer is

<h2>f( - 4) =  - 56</h2>

Step-by-step explanation:

f(x) =  - 3 {x}^{2}  - 8 \\

To find f(-4) , substitute the value of x that's - 4 into f(x). That is for every x in f(x) , replace it with - 4

We have

f( - 4) =  - 3 ({ - 4})^{2}  - 8 \\  =  - 3(16) - 8 \\  =  - 48 - 8 \:  \:  \:  \:  \:

We have the final answer as

f( - 4) =  - 56

Hope this helps you

4 0
3 years ago
Solve the system of equations and choose the correct answer from the list of options d+e =12 -d+e=-8
Svetllana [295]
D + e = 12
-d + e = -8
---------------
2e = 4
e = 2

d + e = 12
d + 2 = 12
d = 10

Answer: (10,2)
7 0
3 years ago
Which of the following is not a polynomial identity?
olga_2 [115]

Answer:

Option B

Step-by-step explanation:

Option A

a² - b² = (a+ b)(a - b)

It's a polynomial identity.

Option B

a³ + b³ = (a - b)(a² - ab + b²)

It's not a polynomial identity.

Because the identity is,

a³ + b³ = (a + b)(a² - ab + b²)

Option C

a³ - b³ = (a - b)(a² + ab + b²)

It's a polynomial identity.

Option D

(a²+ b²)(c² + d²) = (ac - bd)² + (ad + bc)²

                         = a²c² - 2abcd + b²d² + a²d² + b²c² + 2abcd

                         = a²c² + b²c² + b²d² + a²d²

                         = c²(a² + b²) + d²(a² + b²)

                         = (a²+ b²)(c² + d²)

Therefore, it's a polynomial identity.

Option B will be the answer.

7 0
3 years ago
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