Question

Help anyone i need people with the correct answerrr

Answer 1

Answer:

$\text{area of sector} = \frac{320\pi}{3} \text{ mi}^2$

Step-by-step explanation:

Let's use the formula for the area of the sector:
$\text{area of sector} = (\frac{\theta}{360^\circ}) \pi r^2$,
where r is radius and θ the angle in degrees.

Given information:

r = 16 mi

θ = 150°

Using the formula:

$\text{area of sector} = (\frac{\theta}{360^\circ}) \pi r^2 =\\\\ = (\frac{150^\circ}{360^\circ}) \pi (16\text{ mi})^2 =\\\\ = (\frac{150 \cdot 16^2}{360}) \pi \text{ mi}^2 =\\\\ = (\frac{320}{3}) \pi \text{ mi}^2 =\\\\ = \frac{320\pi}{3} \text{ mi}^2$