A square inscribed in a circle and centered at the origin has points at (2, 2), (- 2, 2), (2, -2) and ( -2, -2). What is the equ
ation of the circle that circumscribes the square?
X^2+y^2=8 is the answer but why?
X^2+y^2=8 is the answer but why?
1 answer:
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First, set the second equation with y as the isolated variable. To do this, subtract 4 from both sides to get
Now that you know the value of y, put that expression in for y in the first equation to get
Then, simplify by adding the x terms together to get
add 4 on both sides to isolate the x terms to get
then divide 6 from both sides to get
Using that x value, plug it into one of the equations as x to find y ( I will use y=3x-4)
x=1 and y=-1 is the answer
Now that you know the value of y, put that expression in for y in the first equation to get
Then, simplify by adding the x terms together to get
add 4 on both sides to isolate the x terms to get
then divide 6 from both sides to get
Using that x value, plug it into one of the equations as x to find y ( I will use y=3x-4)
x=1 and y=-1 is the answer