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3 years ago

Help pleaseeeeeeeeee

Mathematics

1 answer:

Kobotan [32]3 years ago

6 0

Answer:

Step-by-step explanation:

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Help me please!!!!!!!

Ghella [55]

Answer:

Step-by-step explanation:

she can only wear 7 since she only has 7 shoes

8 0

3 years ago

Out of his monthly salary, Josh spends 37.5% on his bills, on groceries, and on transportation. If he decides to save of the rem

qwelly [4]

Answer:

Josh will save 62.5% of his salary

Step-by-step explanation:

We know that John spends 37.5% of his total salary, and we want to know how much he can save

To do this we have to subtract from the total salary that we will represent it with 100% what he spends 37.5%

100% - 37.5% = 62.5%

Josh will save 62.5% of his salary

4 0

3 years ago

Read 2 more answers

Can you define f(0, 0) = c for some c that extends f(x, y) to be continuous at (0, 0)? If so, for what value of c? If not, expla

Ahat [919]

(i) Yes. Simplify $f(x,y)$ .

$\displaystyle \frac{x^2 - x^2y^2 + y^2}{x^2 + y^2} = 1 - \frac{x^2y^2}{x^2 + y^2}$

Now compute the limit by converting to polar coordinates.

$\displaystyle \lim_{(x,y)\to(0,0)} \frac{x^2y^2}{x^2+y^2} = \lim_{r\to0} \frac{r^4 \cos^2(\theta) \sin^2(\theta)}{r^2} = 0$

This tells us

$\displaystyle \lim_{(x,y)\to(0,0)} f(x,y) = 1$

so we can define $f(0,0)=1$ to make the function continuous at the origin.

Alternatively, we have

$\dfrac{x^2y^2}{x^2+y^2} \le \dfrac{x^4 + 2x^2y^2 + y^4}{x^2 + y^2} = \dfrac{(x^2+y^2)^2}{x^2+y^2} = x^2 + y^2$

and

$\dfrac{x^2y^2}{x^2+y^2} \ge 0 \ge -x^2 - y^2$

Now,

$\displaystyle \lim_{(x,y)\to(0,0)} -(x^2+y^2) = 0$

$\displaystyle \lim_{(x,y)\to(0,0)} (x^2+y^2) = 0$

so by the squeeze theorem,

$\displaystyle 0 \le \lim_{(x,y)\to(0,0)} \frac{x^2y^2}{x^2+y^2} \le 0 \implies \lim_{(x,y)\to(0,0)} \frac{x^2y^2}{x^2+y^2} = 0$

and $f(x,y)$ approaches 1 as we approach the origin.

(ii) No. Expand the fraction.

$\displaystyle \frac{x^2 + y^3}{xy} = \frac xy + \frac{y^2}x$

$f(0,y)$ and $f(x,0)$ are undefined, so there is no way to make $f(x,y)$ continuous at (0, 0).

(iii) No. Similarly,

$\dfrac{x^2 + y}y = \dfrac{x^2}y + 1$

is undefined when $y=0$ .

5 0

2 years ago

Factor out the coefficient of the variable 1/2d+6

Dahasolnce [82]

1/2d+6=1/2(d+12)
Leaving us with 0.5 or 1/2

4 0

3 years ago

When Maria finished medical school, she had a student loan. She repaid $27,000 of the loan within two years of graduating. That

Alchen [17]

Answer

$54,000

Equation

x=27,000

2x=54,000

3 0

3 years ago

Help pleaseeeeeeeeee​

Help pleaseeeeeeeeee