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Andre45 [30]
3 years ago
13

PLEASE HELP WILL GIVE THANKS AND BRAINIEST ANSWER!!!!

Mathematics
1 answer:
nataly862011 [7]3 years ago
5 0
The answer I would say is letter C, I'm a bit rusty but I feel that's the answer have a nice day!
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What is the square root of 1/25
wolverine [178]
First simplify the square root of 1/25

-√1/25

Rewrite using the quote by rule for radicals.

-√1/√25

Any root of 1 is 1

-1/√25

Simplify the denominator. (find the square root of 25)

-1/5

The result can be shown in both exact and decimal forms.
Exact form: -1/5
Decimal form: -0.2

6 0
3 years ago
What is 6 + square root of 2<br> what is 6 - square root of 2
Bess [88]

Answer:

12

Step-by-step explanation:

7 0
3 years ago
Solve the equation 3- (2c - 8) = 7 .<br><br> c= ?
kenny6666 [7]

Answer:

here,

or, 3- 2c + 8 = 7

or, 11 - 2c = 7

or, -2c =7 - 11

or, -2c = -4

or, c = -4/ -2

or, c = 2#

hope this solution will be helpful for you!!

8 0
3 years ago
NEED HELP WITH DIAGRAM AND STEP 4!! WILL GIVE BRAINLIEST
Mrrafil [7]

Answer:

bbbbbb

Step-by-step explanation:

gagagaagag

4 0
4 years ago
In how many different ways can 2/15 be represented as 1/a+1/b, if a and b are positive integers with a greater than or equal to
Dmitrij [34]

Answer:

There are three possible combinations of positive integers such that a > b:

(1)  a = 15  and  b = 15

(2)  a = 20  and b = 12

(3)  a = 45  and  b = 9

Step-by-step explanation:

Notice that the possible factors (different from "1") of the denominator "15" are: 3, 5, and 15.

The answer for the case a = 15 and b = 15 is obvious since :

\frac{1}{15} + \frac{1}{15} = \frac{2}{15}

Then the possibility of a multiple of 5 for one of the denominators (let's say 5*n) and a multiple of 3 (let's say 3*m)for the other one  gives the general equation:

\frac{1}{5n} +\frac{1}{3m} =\frac{2}{15}

which should verify the following as we try to solve for one of the unknowns multiplicative factors  which by the way have to be positive for the requirement given in the problem:

\frac{5n+3m}{15mn}  =\frac{2}{15}\\\frac{5n+3m}{mn}  =\frac{2}{1}\\5n+3m=2mn\\\frac{5n+3m}{mn} =2\\\frac{5}{m} +\frac{3}{n} =2\\\frac{5}{m}=2-\frac{3}{n}

This last equation is very simple to analyze using integer values for "n" which would render a positive value on the right hand side, and then check from that set the ones that give an integer for the value "m".

Those found were:

For n=3, and m=5, a=15, and b=15 (the obvious solution discussed above)

\frac{1}{15} +\frac{1}{15}=\frac{2}{15}

For n = 4 and m = 4, a = 20, and b = 12

\frac{1}{20} +\frac{1}{12}=\frac{32}{240}=\frac{2}{15}

and for n=9 and m=3, a=45 and b = 9

\frac{1}{45} +\frac{1}{9}=\frac{54}{405}=\frac{2}{15}

4 0
4 years ago
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