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2 years ago

A bag contains 2 red, 5 blue, and 7 yellow marbles. Find the probability of drawing a yellow or a red.

Mathematics

1 answer:

Ann [662]2 years ago

3 0

Answer:

drawing a red marble would be 2 in a 14 or 1/7 chance n drawing a yellow would be 1/2.

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Which of the following values has 4 significant figures?

Vlad1618 [11]

Answer:

А. 13.07

Step-by-step explanation:

Significant figures are the number of digit from a number that have meanings. The higher the significant figures of a number, the higher its accuracy will be. The only non-zero number will be count as significant figures unless the zero is between two non-zero numbers like 13.07, the zero placed between 3 and 7. Some number also doesn't count as significant figures like the leading zero.

All other option just shows 3 significant numbers, so the answer is 13.07

6 0

3 years ago

A researcher wishes to conduct a study of the color preferences of new car buyers. Suppose that 50%50% of this population prefer

n200080 [17]

Answer:

0.1527

Step-by-step explanation:

Given that a researcher wishes to conduct a study of the color preferences of new car buyers.

Suppose that 50% of this population prefers the color red

15 buyers are randomly selected

Let X be the no of buyers who prefer red.

X has exactly two outcomes red or non red.

Also each buyer is independent of the other

Hence X is binomial with p = 0.5 and n = 15

Required prob =The probability that exactly three-fifths of the buyers would prefer red

= P(X=9)

= $15C9 (0.9)^9 (0.6)^6$

= $5005(0.0000305)=0.1527$

6 0

2 years ago

What is the area of the figure? Explain the steps you take

Tom [10]

Answer:5.6

Step-by-step explanation:multiply 2×2 and then 3.6×2 and then add them 2 and ÷ by 2

7 0

3 years ago

Read 2 more answers

What is the best approximation of the projection of (5,-1) onto (2,6)?

Hatshy [7]

Answer:

Hence, the scalar projection of $\vec a$ onto $\vec b$ = $\frac{\sqrt{10} }{5}$ , and the vector projection of $\vec a$ onto $\vec b$ = $\frac{1}{5} \hat i+\frac{3}{5} \hat j$ .

Step-by-step explanation:

We have given two points $(5, -1)$ and $(2, 6)$ .

Let, $\vec a=5\hat {i}-\hat {j}$ and $\vec b= 2\hat {i}+6\hat{j}$ .

and we have calculate the projection of $\vec a$ onto $\vec b$ .

Now,

For the calculation of projection, first we need to calculate the dot product of $\vec a$ and $\vec b$ .

$\vec a.\vec b=(5\hat {i}-\hat{j}).(2\hat{i}+6\hat{j})$

$=10-6$

$=4$

then, we have to calculate the magnitude of $\vec b$ .

$\mid {\vec {b}}\mid$ = $\sqrt{2^{2}+6^{2} }$ = $\sqrt{40}$ = $2\sqrt{10}$ .

Now, the scalar projection of $\vec a$ onto $\vec b$ = $\frac{\vec a.\vec b}{\mid b\mid}$

= $\frac{4}{2\sqrt{10} }$ $\frac{2}{\sqrt{10} } \times\frac{\sqrt{10} }{\sqrt{10} } =\frac{2\sqrt{10} }{10} = \frac{\sqrt{10} }{5}$

and the vector projection of $\vec a$ onto $\vec b$ = $\frac{\vec a. \vec b}{\mid\vec b \mid^{2} } . \vec b$

= $\frac{4}{40} . (2\hat i+ 6\hat j)$

= $\frac{1}{5} \hat i+\frac{3}{5} \hat j$

Hence, the scalar projection of $\vec a$ onto $\vec b$ = $\frac{\sqrt{10} }{5}$ , and the vector projection of $\vec a$ onto $\vec b$ = $\frac{1}{5} \hat i+\frac{3}{5} \hat j$ .

6 0

3 years ago

My math problem. <br><br> 2+2/2<br><br> Please help me

trapecia [35]

Ok,First Doing2/2=1 and After
2+1=3

6 0

2 years ago

Read 2 more answers