Honestly I do not like bullies. If you are a bully than STOP.

Mathematics

2 answers:

lubasha [3.4K]3 years ago

6 0

Answer:

lol i don't like bullies either

i mean...i say that now...but in first grade i used to be a bully....we don't talk about that tho

anyways have a nice day and show them bullies who's boss

tatyana61 [14]3 years ago

4 0

Exactly no one likes bullies :)

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100 points Help my grades depend on this

ipn [44]

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the tax rate says 15% for the amount over 436
so fist find the amount that is taxable:

1149 - 436 = 713
now multiply that amount by 0.15 ( 15% as a decimal)

713 * 0.15 = 106.95

now add the base tax to that amount for the total amount of tax:
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3 years ago

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Determine the standard variation of the data below. (1, 2, 3, 4, 5)

Ne4ueva [31]

Calculate for the mean/ average of the given numbers:

μ = (1 + 2 + 3 + 4 + 5) / 5 = 3

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S = (1 - 3)² + (2 - 3)² + (3 - 3)² + (4 - 3)² + (5 - 3)²
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Divide this summation by the number of items and take the square root of the result to get the standard deviation.

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4 years ago

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Three security cameras were mounted at the corners of a triangles parking lot. Camera 1 was 110 ft from camera 2, which was 137

Nata [24]

Answer:

<em>Camera 2nd has to cover the maximum angle, i.e. </em> $78.70^\circ$ .

Step-by-step explanation:

Please have a look at the triangular park represented as a triangle $\triangle ABC$ with sides

a = 110 ft

b = 158 ft

c = 137 ft

1st camera is located at point C, 2nd camera at point B and 3rd camera at point A respectively.

We can use law of cosines here, to find out the angles $\angle A, \angle B, \angle C$

As per Law of cosine:

$cos C = \dfrac{a^{2}+b^2-c^2 }{2ab}\\cos B = \dfrac{a^{2}+c^2-b^2 }{2ac}\\cos A = \dfrac{b^{2}+c^2-a^2 }{2bc}$

Putting the values of a,b and c to find out angles $\angle A, \angle B, \angle C$ .

$cos C = \dfrac{110^{2}+158^2-137^2 }{2\times 110 \times 158}\\\Rightarrow cos C = \dfrac{12100+24964-18769 }{24760}\\\Rightarrow cos C =0.526\\\Rightarrow C = 58.24^\circ$

$cos B = \dfrac{110^{2}+137^2-158^2 }{2\times 110 \times 137}\\\Rightarrow cos B = \dfrac{12100+18769 -24964}{30140}\\\Rightarrow cos B = \dfrac{5905}{30140}\\\Rightarrow cos B =0.196\\\Rightarrow B = 78.70^\circ$

$cos A = \dfrac{158^{2}+137^2-110^2 }{2\times 158 \times 137}\\\Rightarrow cos A = \dfrac{24964+18769-12100}{43292}\\\Rightarrow cos A = \dfrac{31633}{43292}\\\Rightarrow cos A = 0.731\\\Rightarrow A = 43.05^\circ$