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Mandarinka [93]
2 years ago
14

Which linear inequality is represented by the graph?​

Mathematics
2 answers:
marin [14]2 years ago
5 0

Answer:

<em>y > 2 / 3x + 3 ; Option C</em>

Step-by-step explanation:

Consider the y - intercept and slope of the following graph;

y - intercept = ( 0, 3 ) In Other Words - 3\\slope = rise / run = 2 / 3, In Other Words- slope = 2 / 3

Now let us formulate an equation given this information;

Take Equation In Form - y = ax + b, where a - slope, b - yintercept,\\y = ax + b, a = 2 / 3, b = 3, substitute\\y = 2 / 3x + 3

If this graph represents a dotted line, the shaded portion being > than that of the line, we can say that instead of the = being in the equation y = 2 / 3x + 3, take a greater than sign!

Solution ; y > 2 / 3x + 3

<em>y > 2 / 3x + 3 ; Option C</em>

enot [183]2 years ago
3 0

Answer:

C

Step-by-step explanation:

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I really dont understand this question, help? i dont need steps or anything
Agata [3.3K]

Answer:

Step-by-step explanation:

135 degrees is an exterior angle. meaning the interior angle is 45. meaning x is 45 because of the isosceles triangle theorem that states if two sides are equal on a triangle then their angles opposite those are congruent. a triangle measures up to 180 in general. so 45 plus 45 is 90. 180 minus 90 is 90. so angle x is 45 and angle y is 90

6 0
2 years ago
If 2a/4=b/4 and b≠0, what does 5b equal in terms of a?
dedylja [7]

Step-by-step explanation:

you must have made a typo here.

none of the answer options are correct for the given problem.

let me just show you what you told me, and how I can solve at least this :

2a/4 = b/4

this simply means (multiply both sides by 4) :

2a = b

so, 5b is then (multiplying both sides by 5) :

5×2a = 5b

10a = 5b

but again, "10a" is not among the offered answers.

so, I don't know if you made a mistake with the basic problem or with the answer options.

8 0
1 year ago
What is the answer? I am so lost- thanks for any help given.
aev [14]

Answer:

i think that the answer is 13 meters

Step-by-step explanation:

7 0
3 years ago
Justin is constructing a line through point Q that is perpendicular to line n. He has already constructed the arcs shown. He pla
krek1111 [17]
<span>B. It must be the same as when he constructed the arc centered at point A. This problem would be a lot easier if you had actually supplied the diagram with the "arcs shown". But thankfully, with a few assumptions, the solution can be determined. Usually when constructing a perpendicular to a line through a specified point, you first use a compass centered on the point to strike a couple of arcs on the line on both sides of the point, so that you define two points that are equal distance from the desired intersection point for the perpendicular. Then you increase the radius of the compass and using that setting, construct an arc above the line passing through the area that the perpendicular will go. And you repeat that using the same compass settings on the second arc constructed. This will define a point such that you'll create two right triangles that are reflections of each other. With that in mind, let's look closely at your problem to deduce the information that's missing. "... places his compass on point B ..." Since he's not placing the compass on point Q, that would imply that the two points on the line have already been constructed and that point B is one of those 2 points. So let's look at the available choices and see what makes sense. A .It must be wider than when he constructed the arc centered at point A. Not good. Since this implies that the arc centered on point A has been constructed, then it's a safe assumption that points A and B are the two points defined by the initial pair of arcs constructed that intersect the line and are centered around point Q. If that's the case, then the arc centered around point B must match exactly the setting used for the arc centered on point A. So this is the wrong answer. B It must be the same as when he constructed the arc centered at point A. Perfect! Look at the description of creating a perpendicular at the top of this answer. This is the correct answer. C. It must be equal to BQ. Nope. If this were the case, the newly created arc would simply pass through point Q and never intersect the arc centered on point A. So it's wrong. D.It must be equal to AB. Sorta. The setting here would work IF that's also the setting used for the arc centered on A. But that's not guaranteed in the description above and as such, this is wrong.</span>
8 0
3 years ago
Read 2 more answers
If both slopes are undefined are they parallel?
SCORPION-xisa [38]

Answer:

If the slopes of the lines are both zero, the lines are horizontal and are parallel by definition. Since the slopes of vertical lines are undefined and not considered equal, vertical lines will not be considered.

I hope this helps you :)

8 0
2 years ago
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