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shtirl [24]
2 years ago
5

Help picture below problem 13

Mathematics
1 answer:
Hitman42 [59]2 years ago
3 0

Answer:

it's obtuse angle...

mark me brainliest

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Please help me with this triangle problem!
Westkost [7]

Answer:

Answer is given below with explanations.

Step-by-step explanation:

By using the results of the similarity theorem

we say that

{y}^{2}  = 4 \times 12 \\  {y}^{2}= 48 \\  {y} =  \sqrt{48}  \\ y = 4 \sqrt{3}

<em>HAVE A NICE DAY</em><em>!</em>

<em>THANKS FOR GIVING ME THE OPPORTUNITY</em><em> </em><em>TO ANSWER YOUR QUESTION</em><em>.</em>

3 0
3 years ago
In right triangle JFK sin(52)= cos(5x-2). What is the measure of the smallest angle in the triangle?
jeyben [28]

Answer:

48°

Step-by-step explanation:

Given the trigonometry equation

sin(52)= cos(5x-2)...1

According to the quadrant:

Sin(θ) = cos(90-θ)

Sin52 = cos(90-52)

Sin52 = cos48... 2

Substituting 2 into 1:

Cos48 = cos(5x-2)

48 = 5x-2

5x = 48+2

5x = 50

x = 10°

The smallest of the angle will be angle 5x-2 = 5(10)-2

= 50-2

= 48°

7 0
3 years ago
Y=300(1+0.06/12)^12t<br><br>i need to answer. no links or I'll report ​
Ghella [55]
Well if you were to solve for y it would be “y=300•1.005^12t
-
If you were to solve for t it’d be “t=In(y/300)/12In(1.005)
5 0
3 years ago
For a sample of eight bears, researchers measured the distances around the bears' chests and weighed the bears. Minitab was used
kkurt [141]

Answer:

Kindly check explanation

Step-by-step explanation:

Given that :

Correlation Coefficient (r) = 0.989

alph=0.05

Number of observations (n) = 8

determine if there is a linear correlation between chest size and weight.

Yes, there exists a linear relationship between chest size and weight as the value of the correlation Coefficient exceeds the critical value.

What proportion of the variation in weight can be explained by the linear relationship between weight and chest size?

To determine the the proportion of variation in weight that can be explained by the linear regression line between weight and chest size, we need to obtain the Coefficient of determination(r^2) of the model.

r^2 = square of the correlation Coefficient

r^2 = 0.989^2 = 0.978121

Hence, about 0.978 (97.8%) of the variation in weight can be explained by the linear relationship between weight and chest size.

4 0
3 years ago
Please help ** revised version ** will give 13 points
hammer [34]
If each math book is 0.75 of a inch wide you would do 18 divided by 0.75= 24. 24 books width can fit into the 18 inches.
3 0
4 years ago
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