Answer : C
we need to the value of f(–1)
Table is given in the question
From the table ,
f(x) = 4 when x= -5, that is f(-5) = 4
f(x) = 0 when x= -1, that is f(-1) =0
f(x)= -1 when x=6, that is f(6) = -1
f(x)= -3 when x=9, that is f(9) = -3
So, the value of f(–1) = 0
First you subtract the two equations
x^2-2x+3-6x
You simplify that and get
x^2+4x+3 = 0
Now we solve using the quadratic formula.
We get x = -1 and x = -3.
Now we find the y values by plugging the x values into the equation.
f(x) is the same as y.
y = (-1)^2 - 2(-1) + 3
y = 1+2+3
y = 6
Now for the other x value.
y = (-3)^2 - 2(-3) + 3
y = 9+9
y = 18
So the two ordered pairs are (-1,6) and (-3,18)
-2 to the 4th power would -2*-2*-2*-2 4*-2*-2 -8*-2=16 so yes Tim is correct
Step-by-step explanation:
Let xy = k, where k is the constant of variation.
By using values of x and y in the table,
we see that (2)(48) = (4)(24) = (12)(8) = 96.
Hence k = 96, which is our answer.