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skad [1K]
3 years ago
13

Solve the problem. When going more than 38 miles per hour, the gas mileage of a certain car fits the model where x is the speed

of the car in miles per hour and y is the miles per gallon of gasoline. Based on this model, at what speed will the car average 15 miles per gallon? (Round to nearest whole number.)

Mathematics
1 answer:
Lubov Fominskaja [6]3 years ago
8 0

Answer:

73 mph

Step-by-step explanation:

The question seems to be incomplete because the model is missing, I found a similar question with the addition of the model, so if we can solve it (see attached image).

We have that the model would be:

y = 43.81 - 0.395 * x

We need to solve for x, if y = 15

Replacing:

15 = 43.81 - 0.395 * x

Solving for x we have:

0.395 * x = 43.81 - 15

0.395 * x = 28.81

x = 28.81 / 0.395

x = 72.9

We are asked to round to the nearest number therefore x = 73.

The car will average 15 miles per gallon at the speed of 73 miles per hour.

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When 0.5(20x – 50y + 36) – 0.25(–100x + 40y – 12) is simplified, what is the resulting expression?
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Sherman has two sequences . The first sequence is described by the explicit rule f(n) = 15n + 4 and the second sequence is descr
Viktor [21]

Answer:

Step-by-step explanation:

Given the explicit function as

f(n) = 15n+4

The first term of the sequence is at when n= 1

f(1) = 15(1)+4

f(1) = 19

a = 19

Common difference d = f(2)-f(1)

f(2) = 15(2)+4

f(2) = 34

d = 34-19

d = 15

Sum of nth term of an AP = n/2{2a+(n-1)d}

S20 = 20/2{2(19)+(20-1)15)

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S20 = 3230.

Sum of the 20th term is 3230

For the explicit function

f(n) = 4n+15

f(1) = 4(1)+15

f(1) = 19

a = 19

Common difference d = f(2)-f(1)

f(2) = 4(2)+15

f(2) = 23

d = 23-19

d = 4

Sum of nth term of an AP = n/2{2a+(n-1)d}

S20 = 20/2{2(19)+(20-1)4)

S20 = 10(38+19(4))

S20 = 10(38+76)

S20 = 10(114)

S20 = 1140

Sum of the 20th terms is 1140

7 0
3 years ago
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