The formula for momentum is:
M=Mass*Velocity
From this formula we can derive the formula for velocity:
V=Momentum/Mass
We already know momentum (10 kg m/s) and mass (2 kg). Let's plug in the numbers into the formula:
V=10/2
V=5 m/s
Answer:
a) P ( 3 ≤X≤ 5 ) = 0.02619
b) E(X) = 1
Step-by-step explanation:
Given:
- The CDF of a random variable X = { 0 , 1 , 2 , 3 , .... } is given as:
Find:
a.Calculate the probability that 3 ≤X≤ 5
b) Find the expected value of X, E(X), using the fact that. (Hint: You will have to evaluate an infinite sum, but that will be easy to do if you notice that
Solution:
- The CDF gives the probability of (X < x) for any value of x. So to compute the P ( 3 ≤X≤ 5 ) we will set the limits.

- The Expected Value can be determined by sum to infinity of CDF:
E(X) = Σ ( 1 - F(X) )

E(X) = Limit n->∞ [1 - 1 / ( n + 2 ) ]
E(X) = 1
Answer:
96 + 150 + 2x + x = 360⁰
240 + 3x = 360⁰
3x = 120
x = 40⁰ hope it's help you