Answer:b is the right choice hopefully dont be mad if it is wrong
Step-by-step explanation:
<h3>#End behaviour:-</h3>
#1
#2
<h3>#Degree:-</h3>
Find nodes
#1
#2
It's a parabola so it's the graph of a quadratic equation.
<h3>Real zeros</h3>
#1
#2
Answer:
(8, -1)
Step-by-step explanation:
the solution is where they intersect. (x, y) and x is 8 while y is -1
Option C.
No matter how much n decreases, -1 will always be bigger than 9n.
![\bf \textit{surface area of a cylinder}\\\\ SA=2\pi r(h+r)~~ \begin{cases} r=radius\\ h=height\\[-0.5em] \hrulefill\\ r=13.5\\ h=90 \end{cases}\implies SA=2\pi (13.5)(90+13.5) \\\\\\ SA=27\pi (103.5)\implies SA=2794.5\pi \implies SA\approx 8779.18](https://tex.z-dn.net/?f=%5Cbf%20%5Ctextit%7Bsurface%20area%20of%20a%20cylinder%7D%5C%5C%5C%5C%20SA%3D2%5Cpi%20r%28h%2Br%29~~%20%5Cbegin%7Bcases%7D%20r%3Dradius%5C%5C%20h%3Dheight%5C%5C%5B-0.5em%5D%20%5Chrulefill%5C%5C%20r%3D13.5%5C%5C%20h%3D90%20%5Cend%7Bcases%7D%5Cimplies%20SA%3D2%5Cpi%20%2813.5%29%2890%2B13.5%29%20%5C%5C%5C%5C%5C%5C%20SA%3D27%5Cpi%20%28103.5%29%5Cimplies%20SA%3D2794.5%5Cpi%20%5Cimplies%20SA%5Capprox%208779.18)
well, the last part will be with a calculator, but you can simply use the area in π terms.