Use the exponential regression equation y=1.63(1.84)x to estimate the value of y when x = 5.

From the sum of 3a^2−ab−2b^2 and 2a^2+5ab−3b^2 subtract a^2−3ab−4b^2

$(3a^2-ab-2b^2) + (2a^2+5ab-3b^2) - (a^2-3ab-4b^2)$

First we distribute the negative throughout the last polynomial:

$(3a^2-ab-2b^2) + (2a^2+5ab-3b^2) + (-a^2+3ab+4b^2)$

Combine like terms:

$4a^2 + 7ab - b^2$

3 0

3 years ago

Help help help help help help

Keith_Richards [23]

Answer:

Solution,

or,125°=5x+30°[Being vertically opposite angles]

or,125°-30°=5x

or,95°=5x

or,x=95°/5

Hence,x=19°

Step-by-step explanation:

3 0

2 years ago

What is the effect on the graph of the function f(x) = x^2 when f(x) is changed to f(x − 6)

olya-2409 [2.1K]

Answer:

The comparison graph is also attached in 3rd figure. In the 3rd figure, the graph with vertex (0, 0) is representing $f(x) = x^2$ and $\:f\left(x\right)=\left(x-6\right)^2$ is represented as being shifted 6 units to the right as compare to the function $f(x) = x^2$ .

Step-by-step explanation:

When we Add or subtract a positive constant, let say c, to input x, it would be a horizontal shift.

For example:

Type of change Effect on y = f(x)

$y = f(x - c)$ horizontal shift: c units to right

So

Considering the function

$f(x) = x^2$

The graph is shown below. The first figure is representing $f(x) = x^2$ .

Now, considering the function

$\:f\left(x\right)=\left(x-6\right)^2$

According to the rule, as we have discussed above, as a positive constant 6 is added to the input, so there is a horizontal shift, 6 units to the right.

The graph of $\:f\left(x-6\right)=\left(x-6\right)^2$ is shown below in second figure. It is clear that the graph of $\:f\left(x-6\right)=\left(x-6\right)^2$ is shifted 6 units to the right as compare to the function $f(x) = x^2$ .

The comparison graph is also attached in 3rd figure. In the 3rd figure, the graph with vertex (0, 0) is representing $f(x) = x^2$ and $\:f\left(x\right)=\left(x-6\right)^2$ is represented as being shifted 6 units to the right as compare to the function $f(x) = x^2$ .