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san4es73 [151]
3 years ago
5

Make subject of the formula ​

Mathematics
1 answer:
ella [17]3 years ago
4 0

Answer:This is what i could solve hope it helps :)

Number17

H = \frac{m(v^2-u^2}{2gx} \\Cross - multiply\\2Hgx = m (v^2-u^2)\\2Hgx = mv^2-mu^2\\\frac{2Hgx+mu^2}{m} = \frac{mv^2}{m} \\Divide -both -sides-of-the-equation-by-m\\v^2 = \frac{2Hgx+mu^2}{m}\\Square - root-both -sides -to -eliminate the square\\v =\sqrt{\frac{2Hgx+mu^2}{m}}

Step-by-step explanation:

Number 19

T =2\pi \sqrt{\frac{1}{MH}}\\Divide - both - sides-of-the-equation-by 2\pi\\\frac{2\pi \sqrt{\frac{1}{MH}}}{2\pi }=\frac{T}{2\pi }\\\sqrt{\frac{1}{MH}}=\frac{T}{2\pi }\\SQUARE-BOTH -SIDES\\\left(\sqrt{\frac{1}{MH}}\right)^2=\left(\frac{T}{2\pi }\right)^2\\\frac{1}{MH}=\frac{T^2}{4\pi ^2}\\CROSS-MULTIPLY\\MHT^2={4\pi ^2\\\\DIVIDE BOTH SIDES OF THE EQUATION BY HT^2\\M=\frac{4\pi ^2}{HT^2}

Number 20 &21

A =\frac{1}{2} m(v^2-u^2)\\Divide both sides by \frac{1}{2} m\\\frac{\frac{1}{2}m\left(v^2-u^2\right)}{\frac{1}{2}m}=\frac{A}{\frac{1}{2}m}\\2Am = v^2-u^2\\Move- v^2- to- the -other -side- to- isolate- u\\\\u^2 = 2Am-v^2\\Square-root-both-sides-to -eliminate-the-square-on-u.\\u = \sqrt{2Am-v^2}

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What can you buy with a credit card ?
telo118 [61]

Answer:

Most goods and services

Step-by-step explanation:

A credit card can be used to purchase most goods and services, whether they are legal or not.

8 0
3 years ago
What is a rational number between -1/4 and 2/5
kramer
1/5

Any number that can be written in fraction form is a rational number, so numbers like -1/8, 0, 1/4, etc. all work.
4 0
3 years ago
Factorise completely:<br> 1. 3xy - x<br>2. 4a² - 9​
Amanda [17]

Answer:

x(3y - 1) and (2a - 3)(2a + 3)

Step-by-step explanation:

(1)

3xy - x ← factor out x from each term

= x(3y - 1)

(2)

4a² - 9 ← is a difference of squares and factors in general as

a² - b² = (a - b)(a + b) , then

4a² - 9

= (2a)² - 3²

= (2a - 3)(2a + 3)

6 0
3 years ago
Solve the following equation then place the correct number in the box provided. X/3 - 4 = 10
ivann1987 [24]
X = 42

x/3 - 4 = 10
+ 4 +4
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•3 •3
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4 0
3 years ago
Please help with 6 and 7
Maru [420]

Answer:

6a) i- 2hrs 36mins  ii- 3hrs 12mins

b) car A≈ 76.9km/h  car B≈ 62.5km/h

c)------

7a) 35km

b) car A=75km  car B=60km

c) 30km

d) car A≈36mins  car B≈48mins

Step-by-step explanation:

6a) Using the graph follow the lines until they finish then go downwards until you get to the x-axis. The x-axis is going up by 12mins for each square.

b) Using the answer from a, you divide 200km by the time.

For car A 2hrs 36mins becomes 2.6 because 36mins/60mins=0.6

∴ car A: 200/2.6≈ 76.92km/h

For car B 3hrs 12mins becomes 3.2 because 12mins/60mins=0.2

∴ car B: 200/3.2≈ 62.5km/h

7a) Using the graph go down from where the line of car A finished to meet car B. The y-axis is going up by 5km for each square.

b) Starting from the x-axis at 1 hour go upwards to see where you meet the car B line (60km) and car A line(75km). (sorry if that does not really make sense).

c) Difference from car A line to car B:

155km-125km=30km

d) Going across from 50km meet car A line and go down to see it has been travelling for approx. 36mins. Then continue across to car B line, go down to see it reached 50km at approx. 48mins.

Hope this helps.

5 0
4 years ago
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