Answer:
A. The results are close to a 1:1 ratio of plants with red flowers to plants with white flowers. Therefore, the genotypes of the parents are Rr and rr.
Explanation:
I took the test and got it right.
Answer:
a. purple allele (C) = 0.609, pink allele (c) = 0.391
b. purple homozygotes = 371, pink homozygotes = 153, heterozygotes = 476
Explanation:
Given -
Purple flowers - 847
Pink flowers - 153
The frequency of recessive genotype i.e
Frequency of recessive allele i.e q is equal to
As per hardy Weinberg's first equilibrium equation -
Frequency of purple homozygous species
Number of purple homozygous species 
Number of pink homozygous species 
Heterozygous species is equal to
Answer:
We collect data and information needed to address both current and emerging science and management needs. Exploration helps to ensure that ocean resources are not just managed, but managed in a sustainable ways. ;)
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Answer:
the tendency toward a relatively stable equilibrium between interdependent elements, especially as maintained by physiological processes.
Answer:
A: Unlike DNA, XNA replicates conservatively
Explanation:
<em>The replication of the DNA is </em><em>semi conservative.</em><em> This means that newly replicated double helix DNAs usually consist of one parental strands and one newly synthesized strands. The parental DNA unwinds and each strand serves as template for the synthesis of complementary strands.</em>
In the case of XNA, the two strands of parental XNA were found intact, meaning that the newly produced XNA consist of two newly synthesized strands. This thus means that the replication process is conservative.
Hence, unlike DNA replication that is semi conservative, XNA replication is conservative.
