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3 years ago

Simplify the following expression.

Mathematics

1 answer:

lana66690 [7]3 years ago

6 0

Answer:

D. log(9)

Step-by-step explanation:

$log(9x^{5})+5log(\frac{1}{x})$

Remember: $A log (x) = log(x^{A})$

$log(9x^{5})+log((\frac{1}{x})^{5})$

Remember: $log_{a} (x)+log_{a}(y)=log_{a}(xy)$

$log(9(\frac{1}{x})^{5}x^{5})$

Simplify...

$log(9)$

Hope this helps! If you need steps for simplifying, just ask! :]

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An airline is planning its staffing needs for the next year. If a new route is approved, it will hire 858 new employees. If a n

stealth61 [152]

Answer:

$E(X) = \sum_{i=1}^n X_i P(X_i)$

And from the problem we know the following:

$P(X_1) = 0.34 , X_1 =858$ represent the condition if the route is approved

$P(X_2) = 1-0.34=0.66 , X_1 =157$ represent the condition if the route is NOT approved

Then replacing in the formula for the expected value we got:

$E(X) = 858*0.34 + 157*0.66 = 395.34$

So then the expected number of new employees to be hired by the airline based on the conditions given is between 395 and 396.

Step-by-step explanation:

For this cae we can define the random variable X who represent the number of new employees to be hired by the airline and we can find the expected value with the following general formula:

$E(X) = \sum_{i=1}^n X_i P(X_i)$

And from the problem we know the following:

$P(X_1) = 0.34 , X_1 =858$ represent the condition if the route is approved

$P(X_2) = 1-0.34=0.66 , X_1 =157$ represent the condition if the route is NOT approved

Then replacing in the formula for the expected value we got:

$E(X) = 858*0.34 + 157*0.66 = 395.34$

So then the expected number of new employees to be hired by the airline based on the conditions given is between 395 and 396.

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3 years ago

8 identical pens cost £12 work out the cost of 10 of these pens

katen-ka-za [31]

Ok. So, if 8 pens cost £12. Then we would divide £12 by 8. Each pen costs £1.5.

So now we are going to multiply £1.5 and 10. £1.5*10=15.

The total of 10 pens is £15.

I hope this helps, if you need any additional help, just ask. I am here to help you as needed.

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3 years ago

Marco has a collection of 38 state quarters. If 3/5 of his quarters are dated 2005, what is the approximate value of the quarter

Kipish [7]

First, find the number of quarters that are dated 2005 by multiplying 38*(3/5)
You get 22.8, so you round that to the nearest whole number (23)
Then, since each quarter is worth ($.25) you multiply the number of coins by the worth.
23*.25=$5.75

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4 years ago

Read 2 more answers

Three less than 3 times a number, n, is

tankabanditka [31]

The equation is:

3n - 3 = 2n + 19

=> 3n - 2n = 19 + 3

=> n = 22

So, the answer is 22.

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3 years ago

2 1/9 + (2/9)+3 5/9 equals what

Ugo [173]

Answer:

look it up on desmos

Step-by-step explanation:

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