Let us assume the number of CDs Kate had = x
Number of CDs given to Sue = 5x/6
Number of CDs given to Joan = (5x/6) * ( 7/8)
= 35x/48
Number of CDs given to Ann = (35x/48) * (3/5)
= 7x/16
Total number of CDs Ann received = 70
Then
7x/16 = 70
x = 160
From the above deduction, it can be concluded that the number of CDs that Kate originally had was 160. I hope that this is the answer that has actually come to your help.
Answer:
Step-by-step explanation:
(a) 3 of the 6 numbers on the die are even, so the probability that one of them will show is 3/6 = 1/2.
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(b) 2 of the 6 numbers on the die are less than 3, so the probability that one of them will show is 2/6 = 1/3.
Answer:
See Explanation
Step-by-step explanation:
Given
--- Number of tryouts
Required
Determine the average distance
<em>This question has missing details, as the distance he hits the ball in each tryout is not given. However, I'll give a general explanation.</em>
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The mean is calculated as:
means the sum of the distance in each tryout.
Assume that the distance in the 10 tryouts are:
So, the mean is:
<em>So, the average distance is 6.5</em>
Find the perimeter of the scale artwork
P=2(l+w)
P=2(2.5+1.75)
=2(4.25)= 8.5 in
1 in = 0.5 ft
8.5in = 0.5(8.5)
=4.25ft = 51 in
the actual perimeter is 51 in or 4.25 ft
I believe it is 8,000 grams :).