We have that
<span> |x+6| >= 5
step 1
resolve for (x+6)>=5------> x>=5-6-------> x>= -1
the solution is the interval </span>(-1, ∞)
<span>
step 2
resolve for -(x+6) >=5------> -x-6 >=5----> -x >= 5+6---> -x>=11----> x<=-11
</span>the solution is the interval (-∞, -11)
<span>
using a graph tool
see the attached figure
the solution is the interval (-</span>
∞, -11) ∩ (-1, ∞)
Hey there!
It can be both. It's a multiple of 8 because 8 times 5 is 40, but it's also a factor of 120 because 80 times 3 is 120.
Hope this helps!
1.500 since 45 rounds to 50
Let the lengths of the sides of the rectangle be x and y. Then A(Area) = xy and 2(x+y)=300. You can use substitution to make one equation that gives A in terms of either x or y instead of both.
2(x+y) = 300
x+y = 150
y = 150-x
A=x(150-x) <--(substitution)
The resulting equation is a quadratic equation that is concave down, so it has an absolute maximum. The x value of this maximum is going to be halfway between the zeroes of the function. The zeroes of the function can be found by setting A equal to 0:
0=x(150-x)
x=0, 150
So halfway between the zeroes is 75. Plug this into the quadratic equation to find the maximum area.
A=75(150-75)
A=75*75
A=5625
So the maximum area that can be enclosed is 5625 square feet.