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Fudgin [204]
3 years ago
12

Determine the value of the variables a, b, and c when simplifying and evaluating the expression. 3^8/3^4 = a^b = c

Mathematics
2 answers:
Mnenie [13.5K]3 years ago
8 0

Answer:

3, 4, 81

Step-by-step explanation:

plz thank

Nitella [24]3 years ago
6 0

Answer:

work is shown and pictured

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Rewrite standard form equation in graphing form and then sketch the graph
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3 years ago
What are the solutions of |x+6| greater than or equal to 5? Write the solutions as either the union or the intersection of two s
sukhopar [10]
We have that
<span> |x+6| >= 5
step 1
resolve for (x+6)>=5------> x>=5-6-------> x>= -1
the solution is the interval </span>(-1, ∞)
<span>
step 2
resolve for -(x+6) >=5------> -x-6 >=5----> -x >= 5+6---> -x>=11----> x<=-11
</span>the solution is the interval (-∞, -11)
<span>
using a graph tool
see the attached figure

the solution is the interval (-</span>∞, -11) ∩ (-1, ∞)

8 0
3 years ago
Is 40 a multiple or a factor
gladu [14]
Hey there!
It can be both. It's a multiple of 8 because 8 times 5 is 40, but it's also a factor of 120 because 80 times 3 is 120.
Hope this helps!
5 0
2 years ago
Round the number to the place indicated.<br> Round to the nearest tenth: 1.4511
Evgen [1.6K]
1.500 since 45 rounds to 50
8 0
3 years ago
A rectangular area is to be fenced in with 300 feet of chicken wire. find the maximum area that can be enclosed.
GarryVolchara [31]
Let the lengths of the sides of the rectangle be x and y. Then A(Area) = xy and 2(x+y)=300. You can use substitution to make one equation that gives A in terms of either x or y instead of both.

2(x+y) = 300
x+y = 150
y = 150-x

A=x(150-x) <--(substitution)

The resulting equation is a quadratic equation that is concave down, so it has an absolute maximum. The x value of this maximum is going to be halfway between the zeroes of the function. The zeroes of the function can be found by setting A equal to 0:
0=x(150-x)
x=0, 150

So halfway between the zeroes is 75. Plug this into the quadratic equation to find the maximum area.

A=75(150-75)
A=75*75
A=5625

So the maximum area that can be enclosed is 5625 square feet.
6 0
3 years ago
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