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2 years ago

Determine the value of the variables a, b, and c when simplifying and evaluating the expression. 3^8/3^4 = a^b = c

Mathematics

2 answers:

Mnenie [13.5K]2 years ago

8 0

Answer:

3, 4, 81

Step-by-step explanation:

plz thank

Nitella [24]2 years ago

6 0

Answer:

work is shown and pictured

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The drying times for a certain type of cement are normally distributed with a standard deviation of 30 minutes. A researcher wis

IceJOKER [234]

Answer:

h. 36

Step-by-step explanation:

For a 68.26% confidence, z = 1.0.

Standard deviation (s) = 30 minutes

The sample size needed to assure that the sample mean does not differ from the true mean by more than 5 minutes is given by:

$5\geq z*\frac{s}{\sqrt n}\\\sqrt n\geq 1*\frac{30}{5}\\n\geq 36$

The sample size needed is 36.

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Step-by-step explanation:

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2 years ago

Solve the given initial-value problem. the de is of the form dy dx = f(ax + by + c), which is given in (5) of section 2.5. dy dx

shutvik [7]

$\dfrac{\mathrm dy}{\mathrm dx}=\cos(x+y)$

Let $v=x+y$ , so that $\dfrac{\mathrm dv}{\mathrm dx}-1=\dfrac{\mathrm dy}{\mathrm dx}$ :

$\dfrac{\mathrm dv}{\mathrm dx}=\cos v+1$

Now the ODE is separable, and we have

$\dfrac{\mathrm dv}{1+\cos v}=\mathrm dx$

Integrating both sides gives

$\displaystyle\int\frac{\mathrm dv}{1+\cos v}=\int\mathrm dx$

For the integral on the left, rewrite the integrand as

$\dfrac1{1+\cos v}\cdot\dfrac{1-\cos v}{1-\cos v}=\dfrac{1-\cos v}{1-\cos^2v}=\csc^2v-\csc v\cot v$

Then

$\displaystyle\int\frac{\mathrm dv}{1+\cos v}=-\cot v+\csc v+C$

and so

$\csc v-\cot v=x+C$

$\csc(x+y)-\cot(x+y)=x+C$

Given that $y(0)=\dfrac\pi2$ , we find

$\csc\left(0+\dfrac\pi2\right)-\cot\left(0+\dfrac\pi2\right)=0+C\implies C=1$

so that the particular solution to this IVP is

$\csc(x+y)-\cot(x+y)=x+1$

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9. Verizon offers a cell phone plan that includes a flat fee of $85 per month for the first phone and $7.50 a

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Answer:

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Step-by-step explanation:

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2 years ago

Read 2 more answers

Hi can someone please answer my question. thank you ❤️

Ne4ueva [31]

Hope this helps, have a great!!

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2 years ago