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Kipish [7]
3 years ago
9

If a restaurant sells 6,000 meals in one month, at an average price of 17 per meal for the customer and an average cost of $4.60

per meal for the restaurant, what is the percentage increase from the restaurant price to the restaurant cost?
Mathematics
1 answer:
mash [69]3 years ago
4 0

Answer:

The percentage increase from the restaurant price to the restaurant cost = 269.56%

Step-by-step explanation:

An average price of per meal for the customer= $17

An average cost of per meal for the restaurant= $4.60

Difference in price = 17-4.60

Difference in price =  $12.4

So, the percentage increase from the restaurant price to the restaurant cost =\frac{12.4}{4.60} \times 100

The percentage increase from the restaurant price to the restaurant cost = 269.56%

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Write the fraction 8/9 as a percent round to the nearest hundredth of a percent were necessary?
Flura [38]

Answer:

A

Step-by-step explanation:

To turn a fraction into a percent, you divide the numerator by the denominator.

8 divided by 9 = .8 repeated

To turn it into a percent, you move the decimal to the right 2 spaces.

.8 turns into 88.8 repeated

Then you round to the nearest hundredth

88.8 repeated rounds to 88.89.

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angle 1+angle 2 = 180 degrees

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2 years ago
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3 years ago
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Answer:

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7 0
3 years ago
Solve |y + 2| > 6 i dont understand this, please help
Lisa [10]

y < - 8  or y > 4

inequalities of the form | x | > a always have solutions of the form

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we have to solve

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or

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these can be combined using interval notation

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As a check

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7 0
3 years ago
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