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ohaa [14]
3 years ago
8

Write the point-slope equation of the line that goes through (5, 3) with a slope of -12.

Mathematics
2 answers:
atroni [7]3 years ago
8 0

Step-by-step explanation:

Point slope equation:

y - y1 = m(x - x1)

Insert the values:

y - 3 = -12(x - 5)

VLD [36.1K]3 years ago
7 0

Answer:

y-3=-12(x-5)

Step-by-step explanation:

Point Slope form is: y-y_1=m(x-x_1)

Where:

(x_1,y_1)-\text {Coordinate Point}\\m-\text{Slope}

In the given question, the slope is -12 and the point given is (5,3).

So:

m=-12\\(x_1,y_1)=(5,3)

Replace the variables with the appropriate values.

We get:

y-3=-12(x-5)

So, y-3=-12(x-5) should be your answer.

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Food allergies affect an estimated 7% of children under age 5 in the US. What is the probability that in a kindergarden class of
bezimeni [28]

Answer:

Probability of atleast one of 12 student has food allergies ≈ 0.58 ( approx)

Step-by-step explanation:

Given: Probability of a children under age 5 has food allergies = 7%

                                                                                                        =\frac{7}{100}

To find : Probability of atleast one of 12 student has food allergies

Probability of a chindren under age 5 does not have food allergies = 1-\frac{7}{100}

                  ⇒ prob = \frac{93}{100}

now we find Probability of atleast one of 12 student has food allergies this means we have to find prob of 1 student, 2 student, 3 student, till 12 student have allergy out of 12 student of class then add all prob.

But instead of finding all these probability we find probability of student having no allergy.i.e., 0 student then subtract it from 1(total probability)

Probability of 0 student having allergy out of 12 student = (\frac{93}{100})^{12}

Therefore, Probability of atleast one of 12 student has food allergies

                  = 1-(\frac{93}{100})^{12}

                  = 0.581403702521

                  ≈ 0.58 ( approx)

                 

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3 years ago
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ZanzabumX [31]

The two linear equations in two variable is:

12 x + 3 y = 40

7 x - 4 y = 38

(a) For a system of equations in two Variable

a x + by = c

p x + q y = r

It will have unique solution , when

\frac{a}{p}\neq \frac{b}{q}\neq\frac{c}{r}

As, you can see  that in the two equation Provided above

\frac{12}{7}\neq \frac{3}{-4}\neq \frac{40}{38}

So, we can say the system of equation given here has unique solution.

(b). If point (2.5, -3.4) satisfies both the equations, then it will be solution of the system of equation, otherwise not.

1. 12 x+3 y=40

2. 7 x-4 y=38

Substituting , x= 2.5 , and y= -3.4 in equation (1) and (2),

L.H.S of Equation (1)= 1 2 × 2.5 + 3 × (-3.4)

                             = 30 -10.20

                               = 19.80≠ R.H.S that is 40.

Similarly, L H S of equation (2)= 7 × (2.5) - 4 × (-3.4)

                                                  = 17.5 +13.6

                                                  = 31.1≠R HS that is 38

So, you can Write with 100 % confidence that point (2.5, -3.4) is not a solution of  this system of the equation.


5 0
3 years ago
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